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Annette [7]
4 years ago
14

If the line 3x-4y = 0 is tangent in the first quadrant to the curve y = x^3 + k, then k is

Mathematics
1 answer:
Kryger [21]4 years ago
6 0
Find the slope


3x-4y=0
3x=4y
y=3/4x
slope=3/4

take derivitive of y=x^3+k
y=3x^2

that is slope at mystery point
3x^2=3/4
x^2=1/4
x=1/2
input
y=3/4x
y=3/8
so

3/8=(1/2)^3+k
3/8=1/8+k
2/8=k
1/4=k

k=1/4
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