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stich3 [128]
3 years ago
15

Rewrite 2sin2x + 3 cos x − 3 in terms of cos x

Mathematics
1 answer:
Feliz [49]3 years ago
4 0

9514 1404 393

Answer:

  -2cos²(x) +3cos(x) -1

Step-by-step explanation:

Use the "Pythagorean identity" to replace sin²(x).

  sin²(x) +cos²(x) = 1

Then ...

  2sin²(x) +3cos(x) -3 = 2(1 -cos²(x)) +3cos(x) -3

  = -2cos²(x) +3cos(x) -1

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Need help with this
Marrrta [24]

Answer:

law of cosines states c^2=a^2+b^2-2abc

b^2=26^2+24^2-2(26×24)cos 134°

b^2=676+576-1248cos134°

cos134= -0.6946

b^2=1252-12(-0.6946)

12×(-0.6946)= -8.3352

b^2=1252-(-8.3352)

b^2=1252+8.3352

b^2=1260.33

b=√1260.33

b=35.50

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3 years ago
Can anyone help me with this probability problem? Thank you
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Step-by-step explanation: 3/12= .25

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Please answer this is so urgent
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The answer is 4565 / 63


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Solve the following equation-8=(10x-22)/11
Evgen [1.6K]
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Divide both sides by 10
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