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DENIUS [597]
3 years ago
12

W + (-2) = -18 for w. thinks for helping

Mathematics
2 answers:
jeka57 [31]3 years ago
8 0

Answer: w = -16

Step-by-step explanation:

w + (-2) = -18

     +2            +2

       0 (cancels out)              -16

w = -16

Basically, I moved all the terms not containing w to the right side of the equation.

Katen [24]3 years ago
4 0

Answer:

w = -16

Step-by-step explanation:

w + (-2) = -18

-18 - (-2) = w = -16

w= -16

Check your work:

-16 + (-2) = -18

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0.66666667 as a fraction
Ierofanga [76]

Answer:

__________________________________________

    The correct answer is:   " \frac{2}{3} " .

__________________________________________

Note:  Let's assume that this given decimal value  is really:

"0.66666666666666666....."  ;

(non-terminating; but repeating the singing digit, "7" ; yet rounded to:

" 0.66666667 " ;  

then:  " 0.666... "    = \frac{666}{999}  ;

                             

                               =  (666 ÷ 111) / (999 ÷ 111)  ;

                               =  6/9 ;

                              = (6÷3)/(9÷3)  ;

                               =   2/3 ;

                             

                               =   " \frac{2}{3} "

 

                              →  which is our answer.

____________________________________________

 Or:   " 0.6666... "  =  666 ÷ 999 = ?  ;

                        using calculator :

                               =  0.66666667 ;  

        →  which is the "rounded off" number of "0.6666..." ;

                                                                — (infinitely repeating) ;

                  →   So 666 ÷ 999 =

                  →   "  \frac{666}{999} " ;

               

                               =  " \frac{2}{3} " ;  

                               →  Either use a "fraction calculator" ;

       or simplify as aforementioned.    

____________________________________________

Hope this answer is helpful to you!

       Best wishes to you in your academic pursuits

              — and within the "Brainly" community!

____________________________________________

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