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Pie
3 years ago
9

I only need questions 2 and 3 it’s urgent could someone please help?

Mathematics
1 answer:
marta [7]3 years ago
3 0

Answer:

a = x-intercept(s):  ( 3 , 0 )

y-intercept(s):  

( 0 , 6 )

B = x-intercept(s):  

( 10 , 0 )

y-intercept(s):  

( 0 , 4 )

Step-by-step explanation:

#

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On his bike, Jason can travel 8 miles in 50 minutes.
d1i1m1o1n [39]

Answer:

24 miles

Step-by-step explanation:

50 minutes = 8 miles

100 miles = 16 miles

150 minutes = 24 miles

4 0
3 years ago
Read 2 more answers
Calculate the total area of the shaded region.
LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}

7 0
2 years ago
A bag contains coins of rupees 2 Rupees 1 and 50 paise, in ratio of 1 is to 2 is to 4. if the total amount is rupees 72 find how
BabaBlast [244]

Answer:

<u>Final </u><u>answer </u><u>-</u>

number \: of \: 50 \: paise \: coins \: in \: the \: bag = 4x \\ \dashrightarrow{4 \times 12 = 48 \: coins}

hope helpful :D

4 0
2 years ago
Which inequality has a dashed boundary line when graphed? A y&gt;=3/5x+1 B y&gt;= -1/3x+1 C y&gt;3x+1
Ket [755]

Answer: C y>3x+1

Step-by-step explanation:

  • When we graph an  inequality with strictly greater of less than sign ('<' or '>'), then the graph has a dashed boundary line .
  • Further it indicates that it does not include the points on the line.

From all the given options , only C contains inequality with '>' sign .

Hence, y>3x+1 is the inequality has a dashed boundary line when graphed.

hence, the correct option is C.

4 0
3 years ago
A vehicle is purchased for $18,000, with a down payment of $6,098. The balance in financed for three years at an annual rate of
mestny [16]
The Present value of an annuity is given by PV = P(1 - (1 + r/t)^-nt)/(r/t)
where: P is the monthly payment, r is the annual rate = 7% = 0.07, t is the number of periods in one year = 12 and n is the number of years = 3.

18,000 - 6,098 = P(1 - (1 + 0.07/12)^-(3 x 12)) / (0.07/12)
11,902 = P(1 - (1 + 0.07/12)^-36) / (0.07/12)
P = 0.07(11,902) / 12(1 - (1 + 0.07/12)^-36) = 367.50

Therefore, monthly payment = $367.50
7 0
3 years ago
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