Given:
The equation of a circle is:
To find:
The center and radius of the circle.
Solution:
We have,
To make complete square add square of half of x and square of half of y on both sides.
...(i)
The standard form of a circle is:
...(ii)
On comparing both sides, we get
Therefore, the center of the circle is (-2,3) and the radius is 3 units.
An algebra tile configuration shows only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 negative x, 1 negative.
The correct option is B.
Given
Equation;
It is a polynomial that is equal to zero.
Polynomial of variable power 2, 1, and 0 terms are there.
Any equation having one term in which the power of the variable is a maximum of 2 then it is called a quadratic equation.
4x² -1 = 0 is a quadratic equation.
An algebra tile configuration showing only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 negative x, 1 negative.
Then,
The factors of the polynomial is;
Hence, an algebra tile configuration shows only the product spot, which has 9 tiles in 3 columns with 3 rows. First row: 2 + x squared, 1 + x. Second row: 2 + x squared, 1 + x. Third row: 2 negative x, 1 negative.
More about the quadratic equation link is given below.
Answer:
The real solution is .
Step-by-step explanation:
while
So the equation becomes:
We know that . So let's see what
gives us:
.
is the result we wanted.
is therefore a solution.