Question

​A sample is selected from a population with μ = 46 and a treatment is administered to the sample. After treatment, the sample mean is M = 48 with a sample variance of s2 = 16. Based on this information, the size of the treatment effect, as measured by Cohen’s d, is ____.

Answer 1

Answer:

0.125

Step-by-step explanation:

Cohen's d is used to measure the effect size. Larger the value of Cohen's d, larger the effect between two observations.

It is determined by the formula,

$d= \frac{M_{2}-M_{1}}{Standard deviation}$

where M₂ is Mean of 1st group

M₁ is the Mean of the 2nd group.

Here, M₁ = 46, M₂ = 48 and Standard deviation = 16

∴ $d= \frac{48-46}{16}$

⇒ d = 0.125