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3 years ago

What are the solutions of 5x+23>2x−4?

Mathematics

1 answer:

zhuklara [117]3 years ago

4 0

Answer:

answer :

$x > - 9$

solution:

step 1 :

$5x - 2x > - 4 - 23$

step 2 :

$3x > - 27$

step 3 :

$x > \frac{ - 27}{3}$

final step :

$x > - 9$

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Step-by-step explanation:

Given - The circumference of the ellipse approximated by $C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }$ where 2a and 2b are the lengths of 2 the axes of the ellipse.

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Squaring Both sides, we get

$[\frac{C}{2\pi }]^{2} = [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2} } = {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2} } = {{a^{2} + b^{2} }$

$\frac{C^{2} }{2(\pi )^{2} } = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} } - a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} } - a^{2}} = b$

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3 years ago

What are the solutions of 5x+23>2x−4​?

What are the solutions of 5x+23>2x−4?