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Karolina [17]
4 years ago
7

Four consecutive odd integers can be represented by n, n + 2, n + 4 , and n + 6. If the sum of 4 consecutive odd integers is 56,

what are the integers?
Mathematics
1 answer:
Aneli [31]4 years ago
5 0

Answer:

n = 11

Step-by-step explanation:

2+4+6 = 12

n + n + n + n = 4n

56 - 12 = 44

44 = 4n

Divide both sides by 4:

n = 11

Four integers = 11, 13, 15, and 17

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Solve (x + 2 < 5) ∩ (x - 7 > -6).
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<h2>1. {x | 1 < x < 3}</h2>

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HELP, i really need help with these for questions, I’ll give Brainliest to whoever answers first, random answers will be reports
Tomtit [17]

The angles and lengths of each of the given triangles are;

5) m∠B = 57.52°

6) B = 70.81°

7) AB = 55.43 Km

8) AC = 39.06 ft

<h3>How to use cosine rule?</h3>

The cosine rule is expressed as;

c = √[a² + b² - 2ab(cos C)]

5) Using cosine rule;

BC = √[21² + 13² - 2(21*13)(cos 91)]

BC = 24.89

Using sine rule, we can find angle B as;

21/sin m∠B = 24.89/sin 91

sin m∠B = (21 * sin 91)/24.89

sin m∠B = 0.8436

m∠B = sin⁻¹0.8436

m∠B = 57.52°

6) Using cosine rule;

14² = 11² + 13² - 2(11*13)(cos B)]

196 = 121 + 169 - 286(cos B)

cos B = (121 + 169 - 196)/286

cos B = 0.3287

B = cos⁻¹0.3287

B = 70.81°

7) Using cosine rule;

AB = √[24² + 36² - 2(24*36)(cos 134)]

AB = 55.43 Km

8) Using cosine rule;

AC = √[21² + 26² - 2(21*26)(cos 112)]

AC = 39.06 ft

Read more about cosine rule at; brainly.com/question/4372174

#SPJ1

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