For a question like this you need to find the surface area
The formula is :
b x w x h (base x width x height)
So you multiply 3 1/2 x 6 x 5 1/2 = 22.5
Answers 22.5
Hi!
Answer:
A) 331.24
Step-by-step explanation:
To find the area, you need to multiply LxW, (Length x Width) and in this case, since it's a square, the sides are equal. Each side is 18.2 cm, so all we have to do is multiply 18.2 by 18.2, and then we get 331.24, so your answer is option A.
I hope this helps! :)
Answer:
Option "D" is correct $3630
Step-by-step explanation:
At the beginning of the 7th year, the money has been in the account for 6 years.
The simple interest on $3000 at 3.5% for 6 years is I = prt:
(3000) = (.035) = (6) = 360
he amount in the account at the <u>beginning of the 7th year</u> is then the <u>original amount plus</u> the interest <u>$3630.</u>
Answer:
V≈904.78
Step-by-step explanation:
Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.
Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.
Let us try it below:
Sigma notation 1:
10
<span> Σ (2i + 3)
</span>i = 3
@ i = 3
2(3) + 3
12
The first sigma notation does not have the same result, so we move on to the next.
10
<span> Σ (3i + 2)
</span><span>i = 3
</span>
When i = 3; <span>3(3) + 2 = 11. (OK)
</span>
Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.
When i = 4; <span>3(4) + 2 = 14. (OK)
</span>When i = 5; <span>3(5) + 2 = 17. (OK)
</span>When i = 6; <span>3(6) + 2 = 20. (OK)
</span>When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; <span>3(8) + 2 = 26. (OK)
</span>When i = 9; <span>3(9) + 2 = 29. (OK)
</span>When i = 10; <span>3(10) + 2 = 32. (OK)
Adding the results from her 3rd through 10th trials: </span><span>11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.
</span>
Therefore, the total jumps she had made from her third to tenth trips is 172.
