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Alborosie
3 years ago
6

Given: an n-gon Prove: The sum of the measures of the interior angles is 180(n – 2)°. Complete the missing parts of the paragrap

h proof. We are given an n-gon, which has n sides and n vertices. If we choose one of the vertices, we can draw diagonals. These diagonals form triangles. The sum of the interior angle measures of a triangle is degrees. n – 2 triangles would have an interior angle measure sum of . Therefore, the sum of the measures of the interior angles of an n-gon is 180(n – 2)°. Word Bank: n - 2n - 3180 (n - 2)180 Blank 1:

Mathematics
2 answers:
nirvana33 [79]3 years ago
6 0

1.n-3

2.n-2

3.180

4.180(n-2)




ON EDG

icang [17]3 years ago
5 0

Given: an n-gon

Prove: The sum of the measures of the interior angles is 180(n – 2)°.

Complete the missing parts of the paragraph proof.

We are given an n-gon, which has n sides and n vertices.

Answers:

1. If we choose one of the vertices, we can draw <u>n-3</u> diagonals.

2. These diagonals form <u>n-2</u> triangles.

3. The sum of the interior angle measures of a triangle is <u>180</u> degrees.

4. <u>n – 2</u> triangles would have an interior angle measure sum of <u>180</u> degrees.

5. Therefore, the sum of the measures of the interior angles of an n-gon is 180(n – 2)°.

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  • The solution for the compound inequality is: -0.5 < x \leq 2
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--------------------------------

The compound inequality is given by:

-7 < 4x - 5 \leq 3

Thus, we need:

4x - 5 > -7 and 4x - 5 \leq 3

That is, values of x that respect both these conditions.

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For the first inequality:

4x - 5 > -7

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For the second inequality:

4x - 5 \leq 3

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A similar problem is given at brainly.com/question/24009950

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