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3 years ago

Classify the triangle. obtuse equiangular right acute

Mathematics

2 answers:

7nadin3 [17]3 years ago

7 0

Hello There!

The triangle shown in the image would be an acute triangle

An acute triangle is a triangle where all three sides are less than 90°

In the image, none of the angles shown are greater than 90° so this

is an example of an acute triangle

horrorfan [7]3 years ago

4 0

Answer:

Acute

Step-by-step explanation:

Note the definitions:

Obtuse: At least one of the angles are greater than 90°

Equilateral: All angles are congruent & equal to 60°

Acute: All angles are less than 90°

Right: At least one angle is equal to 90°

In this case, the triangle is a D) acute, for it fits the requirement for being an acute... all angles are less than 90°.

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A circular tire has a radius of 5 feet.

Tom [10]

Answer:

78.5 feet

Step-by-step explanation:

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3 years ago

Let an be the sum of the first n positive odd integers.

sesenic [268]

Answer:

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B) An explicit formula for this sequence can be written as: $a_{n} =8*(n+1)$

C) A recursive formula for this sequence can be written as:

$\left \{ {{a_{1} =16} \atop {a_{n} =a_{n-1}+8}} \right.$

Step-by-step explanation:

A) You can find the firs terms of this sequence simply selecting an odd integer and summing the consecutive 3 ones:

$a_{n} = Odd_{n}+Odd_{n+1}+Odd_{n+2}+Odd_{n+3}$ (a.1)

$a_{1}=1+3+5+7=16$

$a_{2}=3+5+7+9=24$

$a_{3}=5+7+9+11=32$

$a_{4}=7+9+11+13=40$

B) Observe the sequence of odd numbers 1, 3, 5, 7, 9, 11, 13(...).

You can express this sequence as:

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If you merge the expression b.1 in a.1, you obtain the explicit formula of the sequence:

$a_{n} = Odd_{n}+Odd_{n+1}+Odd_{n+2}+Odd_{n+3}$ (a.1)

$a_{n} = (2*n-1)+((2*(n+1)-1))+((2*(n+2)-1))+((2*(n+3)-1))$ (b.2)

$a_{n} = 8*n+8$ (b.3)

$a_{n} =8*(n+1)$ (b.s)

C) The recursive formula has to be written considering an initial term and an N term linked with the previous term. You can see an addition of 8 between a term and the next one. So you can express each term as an addition of 8 with the previous one. Therefore, if the first term is 16:

$\left \{ {{a_{1} =16} \atop {a_{n} =a_{n-1}+8}} \right.$ (c.s)

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3 years ago

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