Answer:
Step-by-step explanation:
![if \: the \: question \: is \: f[g(4)] \\ then \: at \: first \: solve \: for \: g(4) \\ g(4) = {4}^{2} \\ f[g(4)] = 4( {4}^{2} ) + 2 \\ f[g(4)] = 4(16) + 2 \\ f[g(4)] =64 + 2 \\ f[g(4)] = \boxed{66}](https://tex.z-dn.net/?f=%20if%20%5C%3A%20the%20%5C%3A%20question%20%5C%3A%20is%20%5C%3A%20f%5Bg%284%29%5D%20%5C%5C%20then%20%5C%3A%20at%20%5C%3A%20first%20%5C%3A%20solve%20%5C%3A%20for%20%5C%3A%20g%284%29%20%5C%5C%20g%284%29%20%3D%20%20%7B4%7D%5E%7B2%7D%20%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D%204%28%20%7B4%7D%5E%7B2%7D%20%29%20%2B%202%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D%204%2816%29%20%2B%202%20%5C%5C%20f%5Bg%284%29%5D%20%20%3D64%20%2B%202%20%5C%5C%20%20%20f%5Bg%284%29%5D%20%20%3D%20%20%5Cboxed%7B66%7D)
The answer is 1 because anything Raised to the power of zero will always be one in one to the power of -2 will be one
Answer:
D. 720cm squared is the answer
The change of the cost changes when the pounds of ham changes. When the pounds of ham is 0, it costs 0 dollars. When the pounds of ham is 3, it costs 12 dollars. The cost changes consistently with the pounds of ham. They change together. Every time the pounds of ham goes up by 3, the cost goes up by 12.
12. I’m sorry I’m horrible at word problems
13. C
14. C
