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Oduvanchick [21]
3 years ago
7

How to find the asymptotes of a hyperbola?

Mathematics
1 answer:
stellarik [79]3 years ago
5 0
Vertical asymptote:
Find the restriction on x. This is the easiest of the three asymptotes you will need to find (even if only two can show at a time). As a hyperbola is in the form: \frac{1}{x}, you only need to find the restriction on the denominator, namely denominator can never be zero. Hence, let the denominator equal to zero to find the vertical asymptote.

Horizontal asymptote:
Find the restriction on y. To do this, you need to simplify the top and bottom to its lowest terms. If it simplifies to a form such as: a + \frac{b}{x}, then the horizontal asymptote becomes y = a. You need to think to yourself, as x grows to infinite, and shrinks to negative infinite, what happens to the function? Does it slowly curve to a stop?

Oblique asymptote:
This is a pretty rare kind, but it still exists, so don't be naive to this sort of asymptote. This is a form of horizontal and vertical asymptote, only it's at an angle. That is, this asymptote is a set of x and y-coordinates that work in unison to produce a curvature or line.

Let's consider: f(x) = \frac{x^{2} - 6x + 7}{x + 5}

Now, in normal term, a horizontal asymptote would have a degree higher in the denominator than in the numerator. However, it's flipped in this case.

Now, you will need to long divide this set of polynomials to yield a straight y = x line, except it's been moved 11 units to the right to yield a y = x - 11 line.

Remember: these exist because the highest power is in the numerator and not the denominator.
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Clare is cycling at a speed of 12 miles per hour. If she starts at a position chosen as zero, what will her position be after 45
mash [69]
45 minutes is 3/4 of an hour, so find 3/4 of 12. 
Divide 12 by 4 to get 1/4 of 12. That is 3. 
3/4 is 3 of those, so multiply it by 3 to get 9.
So, she will have biked 9 miles. 
Hope this helps!
4 0
3 years ago
Read 2 more answers
Choose all that are correct.
Contact [7]

Answer:

The area of a rectangle is 520 square inches. The length is 3 more than twice the width. The equation 520 = 2w2 + 3w can be used to find the length and width of the rectangle.

Step-by-step explanation:

1st statement:

l= 2w+3

A= l × w

520= w×(2w+3)

520= 2w²+ 3w

2nd statement:

length of fencing= w+2l

120= w+2l

l= 60-w/2

A= (60-w/2) × w

A= 60w- w²/2

Hence this statement is incorrect

3rd statement:

H= x

B= x-4

P= x-2

Accoriding to pythagoras theorem

H²=P²+B²

x²=(x-4)²+(x-2)²

x²= x²-8x+16 + x²-4x+4

0= x²-12x+20

Hence this statement is incorrect

4th statement:

two consecutive even numbers are given by n and n+2

So this statement is incorrect

4 0
3 years ago
Helppp meh please please
Hitman42 [59]
Lol your a little kid but hold on
3 0
3 years ago
Read 2 more answers
Please help please solveit​
Aneli [31]
Not 100% sure but I think it’s d
8 0
4 years ago
Perform the indicated operation.<br> -3(-8)(-2)
seraphim [82]

Answer:

-48

Step-by-step explanation:

Multiply all numbers to get -48

6 0
3 years ago
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