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3 years ago

The second one please help I do not understand and if you can please explain

Mathematics

1 answer:

Masja [62]3 years ago

6 0

When a temperature change causes a substance to turn from liquid to sold, we call the process as FREEZING.

For example, if we take a glass of water and keep it in the freezer, water becomes ice in few minutes.

Since the temperature decreases, water freezes and it becomes ice.

In Ice cream shops, they preserve ice creams in freezer box to prevent them from melting.

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Algebraically determine if the relation x = – y2 – 0.1 is symmetrical with respect to the x-axis, y-axis, or the origin.

Nata [24]

I think that It will be symmetric about x axis

8 0

3 years ago

Chase makes 2 gallons of soup for a dinner party. He serves 15 cups of soup to his guests. How many cups of soup will he have le

Vaselesa [24]

1 gallon is equal to 16 cups.

Since Chase made 2 gallons of soup, multiply 16 x 2.
Chase made 32 cups of soup.

If he served 15 cups of soup to his guests, he will have 17 cups of soup left over, because 32 - 15 = 17.

3 0

3 years ago

Read 2 more answers

Find the measure of angle x in the figure below:

FinnZ [79.3K]

x=180-(65+65)

x=180-130

x=50

A=(4*5)/2

A=20/2=10

4 0

3 years ago

You can use a root to undo...

lutik1710 [3]

Answer:

multiplucation problem

Step-by-step explanation:.

8 0

3 years ago

Marcy has 150 to buy packages of hotdogs and hamburgers for her booth at the carnival. Grocery store she found packages of hotdo

bekas [8.4K]

Answer:

Part (A): The required equation will be: $6d+20b=150$

Part (B):The required equation will be: $d=\frac{150-20b}{6}$

Part (C):The required equation will be: $b=\frac{150-6d}{20}$

Step-by-step explanation:

Consider the provided information.

Let d represents number of packages of hot dogs and b represents the number of packages of hamburgers.

Part (a)

It is given that the cost of a package of hot dogs is $6 and cost of a package of hamburger is $20.

The required equation will be: $6d+20b=150$

Part (b) Solve the above equation for d.

Subtract 20b from both sides.

$6d=150-20b$

Divide 6 from both sides.

$d=\frac{150-20b}{6}$

The required equation will be: $d=\frac{150-20b}{6}$

Part (c) Solve the equation for b.

Subtract 6d from both sides.

$20b=150-6d$

Divide 20 from both sides, we get

$b=\frac{150-6d}{20}$

The required equation will be: $b=\frac{150-6d}{20}$

6 0

3 years ago