Which of following best describes the graph f(x) = 4^-x

Describe the location of point (-3, -2, 3) in three-dimensional coordinate space.

Alja [10]

Answer:

The usual way to draw a 3-D grid can be seen below.

The positive z-axis points upwards

The positive y-axis points to the right

The positive x-axis points towards you, or to the front.

And the notation for a point in 3-D is (x, y, z)

In this case, our point is (-3, -2, 3)

Then the location of the point can be described as:

So the x-value is -3, which means that the point is 3 units behind the origin.

The y-value is -2, which means that the point is 2 units at the left of the origin

The z-value is 3, which means that the point is 3 units above the origin.

5 0

3 years ago

Find the values of the variables ( I have five more of these if you will help me pls)

lord [1]

The angles of the figure are complementary, that is, the sum between them is equal to 90º.

Solving:
54º + 4xº = 90º
4xº = 90 - 54º
4xº = 36º
 $x = \frac{36^0}{4^0}$
$\boxed{\boxed{x = 9^0}}\end{array}}\qquad\quad\checkmark$

We have:
54º + 4.xº = 90º
54º + 4.(9º) = 90º
54º + 36º = 90º
90º = 90º (TRUE)

Answer:
The value of the variable is 9º

5 0

3 years ago

Can anyone do 4,5 and 6 for me plz

cricket20 [7]

For question 4, $sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.$

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

$sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.$

Step 2:

Using the above formula, we solve the following values

$sinA = \frac{oppositeside}{hypotenuse}$ $=\frac{a}{c}.$

$cosA = \frac{adjacentside}{hypotenuse}$ $= \frac{b}{c}.$

$tanB= \frac{opposite side}{adjacent side}$ $= \frac{b}{a}.$

$sinJ = \frac{oppositeside}{hypotenuse}$ $= \frac{j}{l}.$

$cosK = \frac{adjacentside}{hypotenuse}$ $= \frac{j}{l}.$

$tanK= \frac{opposite side}{adjacent side}$ $= \frac{k}{j}.$

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

$sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.$

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

$tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277$

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

7 0

3 years ago

One linear function, t(x), can be modeled by the values in the table below. A second linear function can be modeled by the equat

enyata [817]

At x-intercept, y value = 0,

For t(x), x = 1 when y = 0, i.e. x-intercept = 1

for 3x - 2y + 6 = 0, when y = 0,
3x - 2(0) + 6 = 0
3x + 6 = 0
3x = -6
x = -6/3 = -2
i.e. x-intercept = -2

Therefore, t(x) has the highest x-intercept of 1.

7 0

3 years ago

Read 2 more answers

ms knight and ms whitaker are orgaizing their summer clothes. ms yanowitz has 6 boxes ms. whitacker has 5 boxes. they want to or

natima [27]

If they have 11 boxes and 88 shorts there will be 8 shorts in each box

4 0

4 years ago

Which of following best describes the graph f(x) = 4^-x​

Which of following best describes the graph f(x) = 4^-x