Miguel made $168 for 12 hours of work.

lutik1710 [3]

Answer:

(-1,5), (0,4) ,(1,3) ,(3,1) is linear so dont pick it

(-4,-7), (-2,-6), (2,-4), (4,-3) is linear

you know what I'll just say it wait a minute is there like a other option

Step-by-step explanation:

U can tell by graphing them out yourself and if u see a straight line then it linear, and if you see a curved loop then it's non- linear. but I'll do it :)

4 0

2 years ago

Solving a Real-World Problem

lisov135 [29]

Answer:

C would be your answer as the formula for the volume of a cone is pi*r²*h/3

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

What is the equation of this line? Please Help Y=4x Y=-1/4x Y=-4x Y=1/4x

Sveta_85 [38]

Answer: Y=-1/4x

Step-by-step explanation:

A good way to find an equation of a line is to look for the slope. An obvious spot on this line would be when it crosses (0,0), and another one to the right would be when it crosses at (4,-1).

The slope is rise over run, or if we use the two points we found, "rise" would be -1, because it's dropping 1 unit when going from (0,0) to (4,-1), and the "run" would be 4, because it moves to the right 4 from (0,0) to (4,-1).

Putting these two values together we get:

m (slope) = rise / run

m = -1 / 4

Out of all the equations we're given, we can look for the one with a slope of -1/4, which is given to us:

y = (-1/4)x

7 0

2 years ago

Sara is 6 feet 3 3/4in tall and Sam is 5 feet 6in. How much taller is Sara then Sam?

denpristay [2]

Answer:

9 3/4 inches

Step-by-step explanation:

If we are finding how much taller Sara is, we need to subtract

6 ft 3 3/4 - 5 ft 6in

I like to line up vertically

6 ft 3 3/4

- 5 ft 6in

----------------

We need to borrow 1 ft and make it 12 inches

5 ft 3+12 3/4

- 5 ft 6in

----------------

5 ft 15 3/4

- 5 ft 6in

----------------

0 9 3/4 inches

3 0

3 years ago

1. Let f(x, y) be a differentiable function in the variables x and y. Let r and θ the polar coordinates,and set g(r, θ) = f(r co

Olenka [21]

Answer:

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}\\$

Step-by-step explanation:

First, notice that:

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}cos(\frac{\pi}{4}),\sqrt{2}sin(\frac{\pi}{4}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(\sqrt{2}(\frac{1}{\sqrt{2}}),\sqrt{2}(\frac{1}{\sqrt{2}}))\\$

$g(\sqrt{2},\frac{\pi}{4})=f(1,1)\\$

We proceed to use the chain rule to find $g_{r}(\sqrt{2},\frac{\pi}{4})$ using the fact that $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ to find their derivatives:

$g_{r}(r,\theta)=f_{r}(rcos(\theta),rsin(\theta))=f_{x}( rcos(\theta),rsin(\theta))\frac{\delta x}{\delta r}(r,\theta)+f_{y}(rcos(\theta),rsin(\theta))\frac{\delta y}{\delta r}(r,\theta)\\$

Because we know $X(r,\theta)=rcos(\theta)\ and\ Y(r,\theta)=rsin(\theta)$ then:

$\frac{\delta x}{\delta r}=cos(\theta)\ and\ \frac{\delta y}{\delta r}=sin(\theta)$

We substitute in what we had:

$g_{r}(r,\theta)=f_{x}( rcos(\theta),rsin(\theta))cos(\theta)+f_{y}(rcos(\theta),rsin(\theta))sin(\theta)$

Now we put in the values $r=\sqrt{2}\ and\ \theta=\frac{\pi}{4}$ in the formula:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=f_{x}(1,1)cos(\frac{\pi}{4})+f_{y}(1,1)sin(\frac{\pi}{4})$

Because of what we supposed:

$g_{r}(\sqrt{2},\frac{\pi}{4})=f_{r}(1,1)=-2cos(\frac{\pi}{4})+3sin(\frac{\pi}{4})$

And we operate to discover that:

$g_{r}(\sqrt{2},\frac{\pi}{4})=-2\frac{\sqrt{2}}{2}+3\frac{\sqrt{2}}{2}$

$g_{r}(\sqrt{2},\frac{\pi}{4})=\frac{\sqrt{2}}{2}$

and this will be our answer

3 0

2 years ago