Question

What is the area of the two-dimensional cross section that is parallel to face ABC ?

Answer 1

Answer:

The area of the two-dimensional cross section is $30\ ft^{2}$

Step-by-step explanation:

we know that

The two-dimensional cross section that is parallel to face ABC is a triangle congruent with the triangle ABC

Therefore

Calculate the area of triangle ABC

$A=\frac{1}{2}(BC)(AB)$

we have that

Triangles ABC and DEF are congruent

so

$BC=EF=12\ ft$

$AB=5\ ft$

substitute

$A=\frac{1}{2}(12)(5)=30\ ft^{2}$