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tino4ka555 [31]
3 years ago
8

What is the area of the two-dimensional cross section that is parallel to face ABC ?

Mathematics
1 answer:
Umnica [9.8K]3 years ago
8 0

Answer:

The area of the two-dimensional cross section is 30\ ft^{2}

Step-by-step explanation:

we know that

The two-dimensional cross section that is parallel to face ABC is a triangle congruent with the triangle ABC

Therefore

Calculate the area of triangle ABC

A=\frac{1}{2}(BC)(AB)

we have that

Triangles ABC and DEF are congruent

so

BC=EF=12\ ft

AB=5\ ft

substitute

A=\frac{1}{2}(12)(5)=30\ ft^{2}

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Katyanochek1 [597]

The equation showing the relationship between w and t is w = 4t

From the table, we have the following points:

(0,0) and (1,4)

Start by calculating the slope (m)

m = \frac{y_2 -y_1}{x_2 -x_1}

So, we have:

m = \frac{4 -0}{1 -0}

Simplify the numerator and the denominator

m = \frac{4}{1}

Divide 4 by 1

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The equation is then calculated as:

w = m(t - t_1) + w_1

This gives

w = 4(t - 0) + 0

Simplify

w = 4t

Hence, the equation is w = 4t

Read more about linear equations at:

brainly.com/question/14323743

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3 years ago
Paint can only be purchased in 1-quart, 1-gallon, and 5-gallon containers. How much will all supplies for the project cost if th
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Step-by-step explanation:

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3 years ago
A. 12 + 4x = 6x + 10 – 2x
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An equation has infinitely many solutions if it can be manipulated all the way to an identity (i.e. an equality where the right and left hand side are the same). We have:

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The pic is attached.

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Write the place value 5 in number 2252
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