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tino4ka555 [31]
3 years ago
8

What is the area of the two-dimensional cross section that is parallel to face ABC ?

Mathematics
1 answer:
Umnica [9.8K]3 years ago
8 0

Answer:

The area of the two-dimensional cross section is 30\ ft^{2}

Step-by-step explanation:

we know that

The two-dimensional cross section that is parallel to face ABC is a triangle congruent with the triangle ABC

Therefore

Calculate the area of triangle ABC

A=\frac{1}{2}(BC)(AB)

we have that

Triangles ABC and DEF are congruent

so

BC=EF=12\ ft

AB=5\ ft

substitute

A=\frac{1}{2}(12)(5)=30\ ft^{2}

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Answer:

  • y = 2x + 3
  • y = -6x
  • y = -x + 2
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Step-by-step explanation:

<u>Slope-intercept form:</u>

  • y = mx + b

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