Evaluate A2 for A = -4

Mathematics

2 answers:

ratelena [41]3 years ago

6 0

The answer is -8 because -4x2 is -8

In-s [12.5K]3 years ago

5 0

The answer would be -8. heroes how to solve it (-4)2=-8

You might be interested in

A nut-raisin mix costs $5.26 per pound. Rashid buys 15.5 pounds of the mix for a party. Rashid’s estimated cost of the nut-raisi

Svetllana [295]

Answer: $80

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

16/21 divided by 4/9

leonid [27]

16/21 divided by 4/9 is equivalent to 16/21 x 9/4 = 144/84 which reduces to 12/7. So 12/7 is your answer.

7 0

2 years ago

Read 2 more answers

Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centere

Ket [755]

Answer:

$e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...$

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

Step-by-step explanation:

<u>Taylor series</u> expansions of f(x) at the point x = a

$\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...$

This expansion is valid only if $\text{f}\:^{(n)}(a)$ exists and is finite for all $n \in \mathbb{N}$ , and for values of x for which the infinite series converges.

$\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1$

$\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...$

$\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}$