<h2>
Answer:</h2>
<u><em>Usually, random people will say that on your questions page to give you a virus but then that link doesn't look like the same link I see every day. I would still not click it just in case.</em></u>
<h2>
Explanation:</h2>
<em>Have a good one!</em>
<h2>
( ◑‿◑)ɔ┏--┑٩(^◡^ )</h2>
Answer:
Option (c) Remote code exploits aim to escalate attackers’ privileges, while XSS attacks aim to gain access only
Explanation:
- XSS stands for Cross-site Scripting. In this types of attacks, a malicious code is injected in the trusted web sites and it sends the malicious code into the users. The users think that the genuine code was sent but not.
- This involves sending server side scripts which are executed by the user and these may even change the html pages too.
- Remote code exploitation means the user can inject the code and try to gain access. Usually, all the programming languages have evaluation functions if used the user can try to gain the access with this evaluation functions.
- This can lead to the compromise of the whole web server too.So, it is not a good practice to use the evaluation functions by the developers.
- In this type of attack, the attacker tries to inject the code remotely.
- Option (c) is correct and options (a),(b) and (d) are wrong options.
Answer:
#include <iostream>
using namespace std;
int main() {
int a[4][5];//declaring a matrix of 4 rows and 5 columns.
for(int i=0;i<4;i++)
{
for(int j=0;j<5;j++)
{
if(i==3)//initializing last row as 0.
{
a[i][j]=0;
}
else//initializing last row as 1.
{
a[i][j]=1;
}
}
}
for(int i=0;i<4;i++)
{
for(int j=0;j<5;j++)
cout<<a[i][j]<<" ";//printing the matrix.
cout<<endl;
}
return 0;
}
Output:-
1 1 1 1 1
1 1 1 1 1
1 1 1 1 1
0 0 0 0 0
Explanation:
I have created a matrix of size 4 rows and 5 columns.I have used for loops to fill the array.To fill the last row with 0 i have used if statement.else we are filling it with 1.
A router, possibly. Thought I'm not for sure because I'm not in computers and technology
Answer:
a) 3.3
b) 3
Explanation:
1)
As we know ,
CPI = sum of ( instructions× clock cycle)
= 50%(1) + 30%(4) + 20%(8)
= 50% + 120% + 160%
= 330%
= 
= 3.3
⇒CPI = 3.3
2)
Let a = number of cycles on average
As given,
a 10% improvement in performance of P1,
⇒New CPI = 3
⇒3 = 50% + 30% (x) + 20%(8)
⇒3 = 50% + 30% (x) + 160%
⇒3 = 210% + 30%(x)
⇒3 = 2.1 + 0.3x
⇒3 - 2.1 = 0.3x
⇒0.9 = 0.3x
⇒x = 
= 3
⇒x = 3
∴ we get
Number of cycles on average = 3
