Answer:
Points ABC and points OBC form two separate triangles. Triangle ABC is made up of angles BAC, ABC, ACB, while triangle OBC is made up of angles BOC, OBC, OCB. Since interior angles of triangles add up to 180 degrees, m<BAC + m<ABC + m<ACB = 180 and m<BOC + m<OBC + m<OCB = 180. 180 is equal to 180, so m<BAC + m<ABC + m<ACB = m<BOC + m<OBC + m<OCB.
Since OB bisects <ABC and OC bisects <ACB, m<ABO = m<OBC and m<ACO = m<OCB. We can also say that m<ABC = 2m<ABO and m<ACB = 2m<ACO. Substitute and simplify the equation.
m<BAC + m<ABC + m<ACB = m<BOC + m<OBC + m<OCB
m<BAC + 2m<ABO + 2m<ACO = m<BOC + m<ABO + m<ACO
m<ABO + m<ACO = m<BOC - m<BAC
Answer:
= 2n + 6
Step-by-step explanation:
The nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 8 and d = 2 , then
= 8 + 2(n - 1) = 8 + 2n - 2 = 2n + 6
Answer:
4100
Step-by-step explanation:
Rounding means making a number simpler but keeping its value close to what it was. Visual image below of showing different places to round. Given to make rounding's more clear and easier for you.
17128.........................
Answer:
In bold.
Step-by-step explanation:
a. (x+5)^2 – 3x(x+5) x+5 is common
= (x + 5)(x + 5 - 3x)
= (x + 5)(5 - 2x)
b. (x + 5)(5 - 2x) = 0
x = -5, 2.5.
2a. Area of the square = (x + 5)^2
Area of triangle AEB
= 1/2 * base * height
I am assuming that H is the centre of AB , so
Area = x*x
= x^2.
2b
6x^2 = (x + 5)^2
6x^2 = x^2 + 10x + 25
5x^2 - 10x - 25 = 0
x^2 - 2x - 5 = 0
x = [-(-2) +/- sqrt(2^2 - 4*1*-5)] / 2
x = -1.45, 3.45.
(we ignore the negative).
