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sergeinik [125]
3 years ago
11

What would 2(x+5)=16 be on a number line

Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
6 0

Answer:

3

Step-by-step explanation:

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A phone company surveys a sample of current customers to determine if they use their phones most often to text or use the Intern
Gre4nikov [31]

Answer: payment B: 23 customers

plan B text: 13 customers

fraction form: 13/23

Step-by-step explanation:

7 0
3 years ago
Using the order of operations, what should be done first to evaluate (-4) +6-(-3-4) (2) - 5?
defon
The -3-4 that should be done first
4 0
3 years ago
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Troyanec [42]

Answer:

5.5 pints is the answer to this

5 0
2 years ago
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PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK​
Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

  • \theta is the angle
  • A is the side adjacent the angle
  • H is the hypotenuse (the side opposite the right angle)

Given:

  • \theta = ∠KLM
  • A = LN = 8
  • H = KL = 15.2

\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

6 0
2 years ago
Evaluate the limit. lim x-&gt; infinity n/3^x
Sav [38]

Answer:

0

Step-by-step explanation:

Find the following limit:

lim_(x->∞) 3^(-x) n

Applying the quotient rule, write lim_(x->∞) n 3^(-x) as (lim_(x->∞) n)/(lim_(x->∞) 3^x):

n/(lim_(x->∞) 3^x)

Using the fact that 3^x is a continuous function of x, write lim_(x->∞) 3^x as 3^(lim_(x->∞) x):

n/3^(lim_(x->∞) x)

lim_(x->∞) x = ∞:

n/3^∞

n/3^∞ = 0:

Answer:  0

7 0
3 years ago
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