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3 years ago

PLEASE HELP LOOK AT THE PHOTO I GAVE YOU PLEASE D:

Mathematics

2 answers:

valentina_108 [34]3 years ago

8 0

Answer:

1. Less than
2. Greater than
3. Greater than

Explanation:

1. 2/12+3/12 = 5/12<6/12
2. 4/12+3/12+2/12= 9/12>6/12
3. 3/12+1/12+1/12+4/12=9/12>6/12

vova2212 [387]3 years ago

7 0

Answer:

• 2/12 + 3/12 < 6/12
• 4/12 + 3/12 + 2/12 > 6/12
• 3/12 + 1/12 + 1/12 + 4/12 > 6/12

Explanation:

• Question One

Add the fractions together

2/12 + 3/12 = 5/12

Determine which fraction is greater than, less than, or equal to the other

5/12 ? 6/12
5/12 < 6/12

Therefore, 2/12 + 3/12 is less than 6/12.

• Question Two

Add the fractions together

4/12 + 3/12 + 2/12 = 9/12

Determine which fraction is greater than, less than, or equal to the other

9/12 ? 6/12
9/12 > 6/12

Therefore, 4/12 + 3/12 + 2/12 is greater than 6/12.

• Question Three

Add the fractions together

3/12 + 1/12 + 1/12 + 4/12 = 9/12

Determine which fraction is greater than, less than, or equal to the other

9/12 ? 6/12
9/12 > 6/12

Therefore, 3/12 + 1/12 + 1/12 + 4/12 is greater than 6/12.

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A study investigating the relationship between age and annual medical expenses randomly samples 400 individuals in a city. It is

ICE Princess25 [194]

Answer:

The probability is 0.789

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

$\sigma = 16, n = 400, s = \frac{16}{\sqrt{400}} = 0.8$

Find the probability that the mean age of the individuals sampled is within one year of the mean age for all individuals in the city.

Using $\mu = 30$ , this is the pvalue of Z when X = 31 subtracted by the pvalue of Z when X = 29. So

X = 31

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{31 - 30}{0.8}$

$Z = 1.25$

$Z = 1.25$ has a pvalue of 0.8944

X = 29

$Z = \frac{X - \mu}{s}$

$Z = \frac{29 - 30}{0.8}$

$Z = -1.25$

$Z = -1.25$ has a pvalue of 0.1056

0.8944 - 0.1056 = 0.7888

Rounded to three decimal places, 0.789

The probability is 0.789

4 0

3 years ago

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NEED HELP ASAP WILL MARK BRANLIEST!!!!!!

Blababa [14]

The heck, what math are you in?

7 0

3 years ago

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Convert 5700 milligrams into pounds. Round your answer to the nearest hundred

suter [353]

Answer:

It should be 0.012566 rounded

Step-by-step explanation:

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3 years ago

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In the circle below, suppose m VUX = 152° and mZUVW = 77º. Find the following.

bezimeni [28]

Given:

In the circle, $m(\overarc{VUX})=152^\circ$ and $m(\angle MUV)=77^\circ$ .

To find:

The following measures:

(a) $m\angle VUX$

(b) $m\angle UXW$

Solution:

According to the central angle theorem, the central angle is always twice of the subtended angle intercepted on the same same arc.

$m(VUX)=2\times m\angle VWX$

$152^\circ=2\times m\angle VWX$

$\dfrac{152^\circ}{2}=m\angle VWX$

$76^\circ=m\angle VWX$

In a cyclic quadrilateral, the opposite angles are supplementary angles.

UVWX is a cyclic quadrilateral. So,

$m\angle VUX+m\angle VWX=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle VUX+76^\circ=180^\circ$

$m\angle VUX=180^\circ-76^\circ$

$m\angle VUX=104^\circ$

Now,

$m\angle UXW+m\angle UVW=180^\circ$ [Opposite angles of a cyclic quadrilateral]

$m\angle UXW+77^\circ =180^\circ$

$m\angle UXW=180^\circ-77^\circ$

$m\angle UXW=103^\circ$

Therefore, $m\angle VUX=104^\circ$ and $m\angle UXW=103^\circ$ .

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3 years ago

A projectile is launched from ground level with an initial velocity of v0 feet per second. Neglecting air resistance, its height

olya-2409 [2.1K]

Step-by-step explanation:

I've posted solutions in the picture. Rather the ways to solve them. Check and find answers on your own.

Also, I've not solved the problem by differential calculus. You can, obviously, if you're interested. Use it for ease and for tougher equations.

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3 years ago