Answer: 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.
Step-by-step explanation:
Let X be a random variable that represents the speed of the drivers.
Given: population mean : M = 72 miles ,
Standard deviation: s= 3.2 miles
The probability that the drivers are traveling between 70 and 80 miles per hour based on this distribution:
![P(70\leq X\leq 80)=P(\frac{70-72}{3.2}\leq \frac{X-M}{s}\leq\frac{80-72}{3.2})\\\\= P(-0.625\leq Z\leq 2.5)\ \ \ \ \ [Z=\frac{X-M}{s}]\\\\=P(Z\leq2.5)-P(Z\leq -0.625)\\\\\\ =0.9938-0.2660\ \ \ [\text{Using p-value calculator}]\\\\=0.7278](https://tex.z-dn.net/?f=P%2870%5Cleq%20X%5Cleq%2080%29%3DP%28%5Cfrac%7B70-72%7D%7B3.2%7D%5Cleq%20%5Cfrac%7BX-M%7D%7Bs%7D%5Cleq%5Cfrac%7B80-72%7D%7B3.2%7D%29%5C%5C%5C%5C%3D%20P%28-0.625%5Cleq%20Z%5Cleq%202.5%29%5C%20%5C%20%5C%20%5C%20%5C%20%5BZ%3D%5Cfrac%7BX-M%7D%7Bs%7D%5D%5C%5C%5C%5C%3DP%28Z%5Cleq2.5%29-P%28Z%5Cleq%20-0.625%29%5C%5C%5C%5C%5C%5C%20%3D0.9938-0.2660%5C%20%5C%20%5C%20%5B%5Ctext%7BUsing%20p-value%20calculator%7D%5D%5C%5C%5C%5C%3D0.7278)
Hence, 72.78% of the drivers are traveling between 70 and 80 miles per hour based on this distribution.
When y=2 and y=5
1. 2y-1 and (3y-5+y or 4y-5)
when y=2 ; 2(2)-1 = 3 and 4(2)-5=3
when y=5 ; 2(5)-1 = 9 and 4(5)-5=15
----nonequivalent-----
2.5y+4 and (7y+4-2y or 5y+4)
so you don't have to place any value in because 5y+4 and 7y+4-2y are equal,
whatever you place any value in, it will be all the same then
-----equivalent------
and no need to find more
Answer:
12ch/a
Step-by-step explanation:
hope this helped!
<u>4(x + 2) + 3 >= 27</u>
4x + 8 + 3 >= 27
4x + 11 >= 27
4x >= 16
<u>x >= 4</u>
Answer: 0.85 or %85
Fraction = 68 over 80 divide by two twice 17 over
20
Percent = 68/80 = 0.85 x 100 = 85%
Decimal = 0.85
