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3 years ago

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Use what you know about translations of functions to analyze the graph of the function f(x) = (0.5)x−5 + 8. You may wish to grap

h it and its parent function, y = 0.5x, on the same axes. The parent function y = 0.5x is across its domain because its base, b, is such that . The function, f, shifts the parent function 8 units . The function, f, shifts the parent function 5 units .

2 answers:

IrinaVladis [17]3 years ago

5 0

Answer:

The Translation is 5 units to the right and 8 units up

Step-by-step explanation:

* Lets talk about some transformation

- If the function f(x) translated horizontally to the right

by h units, then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left

by h units, then the new function g(x) = f(x + h)

- If the function f(x) translated vertically up

by k units, then the new function g(x) = f(x) + k

- If the function f(x) translated vertically down

by k units, then the new function g(x) = f(x) – k

* Now lets solve the problem

∵ The parent function is y = (0.5)^x

∵ f(x) = (0.5)^x - 5 + 8 after translation

- The x in the first function is (x - 5) in the second function

∴ There is a horizontal translation to the right 5 units

- the first function is (0.5)^x in the second function y = (0.5)^x - 5 + 8

∴ There is a vertical translation up 8 units

* The Translation is 5 units to the right and 8 units up

- Look to the attached graph to more understand

- The purple graph is y = (0.5)^x

- The black graph is f(x) = (0.5)^x-5 + 8

- To check the answer take a point from the y = (0.5)^x as (0 , 1), the

image of this point on f(x) is (5 , 9)

-The point (0 , 1) is shifted 5 units to the right and 8 units up

∴ Its x- coordinate move from 0 to 5, y- coordinate move from 1 to 9

n200080 [17]3 years ago

4 0

Answer:

The parent function y = 0.5x is DECREASING across its domain because its base, b, is such that 0<b<1.

The function, f, shifts the parent function 8 units UP .

The function, f, shifts the parent function 5 units RIGHT .

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