<h2>
<u>hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>you</u><u> </u><u>❣❣</u><u> </u></h2>
<h2>
<em><u>Mark</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>brainliest</u></em></h2>
<em><u>in</u></em><em><u> </u></em><em><u>fraction</u></em><em><u>=</u></em><em><u>29</u></em><em><u>/</u></em><em><u>15</u></em><em><u>0</u></em>
Answer:
11200 for 7 engines for a total of 80 hours
Step-by-step explanation:
You have 8 engines burning 12000 .for 10 hours.
Divide 10 hours into 12000=1200 PER hour.
1200 ÷8 engines = 140 per hour per engine.
140 × # of hours (12)=1680 for 12 hours per engine.
# of engines × 1680 for 12 hour/per engine
5×1680 = 8400 of fuel for 12 hours/5 engine
Then you have 2 that runs 10 hours
2 × 140 per hour per engine =280 × 10 =2800 for 2 engines for 10 hours
8400. + 2800= 11200 of fuel for 6 engines
We known that the figures are similar if and only if the corresponding sides and and angles have the common scale factor. In this item, the scale factor is 0.6. The length of AB is determined by multiplying the length of FG with the scale factor. That is,
AB = FG x scale factor
AB = (12 cm) x 0.6
AB = 7.2 cm
Thus, the length of side AB is 7.2 cm.
Answer:
she subtracted the 5 instead of adding it
Step-by-step explanation:
Answer:
215 students
Step-by-step explanation:
500 divided by 2 = 250
250 - 35 each= 215
