Answer:
H=9;8)
B=(5;4) (ball)
R=(7;0) (hit point)
B'=symetric of B axis perpendicular of x in R
B'=(7+(7-5);4)=(9;4)
Equation BR: y-4=(0-4)/(7-5)(x-5)==>y=-2x+14
Equation RB': y-4=(4-0)/(9-7)(x-9)==>y=2x-14
Is H a point of RB'? y=2x-14 : 8=? 2*9-14==>8=?4 No!
you will not make your putt
Step-by-step explanation:
Answer:
The awnser is 7/4!!!!!!!!
Step 1: Find the slope
(y-y)/(x-x) = (8-8)/(9+4) = 0
Step 2: Substitute into the slope intercept equation
y - y = m(x - x)
y - 8 = 0(x - 9)
If the problem just wants plain, slope intercept form, then this is your answer.
If not, y = 8
The formula is 1/3*height*area of base.
