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3 years ago

Which amount is bigger

Mathematics

2 answers:

erastova [34]3 years ago

8 0

What the two or more numbers or amounts? Something needs to be compared

Neko [114]3 years ago

5 0

Answer: Which amounts?

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Select the correct answer. Which statement is true?

AnnyKZ [126]

Answer:

Step-by-step explanation:

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3 years ago

Combine the like terms to create an equivalent expression: \large{3z+2+(-5z)+6}3z+2+(−5z)+6

rjkz [21]

Answer:11z+20

Step-by-step explanation:3z+2-5z+18z+12-5z+6

Then u bring light terms together

16z+2+12-5z+6

11z+20

8 0

3 years ago

If line n bisects segment CE, find the positive value of x. A.6 B.10 C.15 D.9

givi [52]

9514 1404 393

Answer:

D. 9

Step-by-step explanation:

The segment lengths are equal, so ...

x^2 = 90-x

x^2 +x -90 = 0 . . . . . . add x-90 to put in standard form

(x +10)(x -9) = 0 . . . . . factor

The solutions are the values of x that make the factors zero: -10, 9.

The positive value of x is 9.

8 0

3 years ago

Read 2 more answers

The second sample was the same size as the first, and the proportion of sales identified as organic was 0.4. How does the 95 per

enot [183]

Answer:

The summer interval is wider and has a greater point of estimate

Step-by-step explanation:

Assuming this problem: "An environmental group wanted to estimate the proportion of fresh produce sales indentified as organic in a grocery store. In the winter, the group obtained a random sample of sales from the store and used the data to construct a 95percent z-interval for a proportion (0.087,0.133). Six months later in the summer, the group obtained a second random sample of sales from the store. The second sample was the same size as the first, and the proportion of sales identified as organic was 0.4. How does the 95 percent z-interval for a proportion constructed from the summer sample compare to the winter interval? "

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

We can find the margin of error from the interval given on this case would be:

$ME= \frac{0.133-0.087}{2}=0.023$

And the point of estimate for the proportion obtained would be:

$\hat p = 0.133-0.023=0.11$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =0.023$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.11(1-0.11)}{(\frac{0.023}{1.96})^2}=710.95$

And rounded up we have that n=711

Now we know that we use the same sample size for the new confidence interval. And replacing into the confidence interval formula we got:

$0.4 - 1.96 \sqrt{\frac{0.4(1-0.4)}{711}}=0.364$

$0.4 + 1.96 \sqrt{\frac{0.4(1-0.4)}{711}}=0.436$

And the new 95% confidence interval would be given (0.364;0.436) has a width of 0.436-0.364=0.072. And the width for the previous confidence interval is 0.133-0.087= 0.046. So then the best answer is:

The summer interval is wider and has a greater point of estimate

7 0

3 years ago

From beginning to end, explain the steps required to make a peanut butter and jelly sandwich.

jonny [76]

First take the bread, jelly, peanut butter out and set on the counter, next get a plate and butter knife. Take two pieces of bread and set them on the plate. Next spread peanut butter on one piece of bread with the butter knife. Next spread jelly on the other piece of bread. Finally put the two pieces of bread together with peanut butter side and jelly side touching.

5 0

4 years ago