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Softa [21]
3 years ago
12

Margaux borrowed 63000 on jan. 16 2012 and paid the loan in full on may 13 2012 with 11% interest. Compute the simple interest u

sing two calendar dates

Mathematics
1 answer:
sp2606 [1]3 years ago
6 0

Answer:

  $2234.26

Step-by-step explanation:

The formula is ...

  i = Prt

Filling in the numbers, we have ...

  i = $63000·0.11·(118/366) ≈ $2234.26

The year beginning Jan 16, 2012 and ending on the same date in 2013 has 366 days, so we use that for the number of days in the year. Similarly, the day Feb 29, 2012 adds one day to the interest-earning period, so there are a total of 118 days between 1/16/2012 and 5/13/2012.

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qwelly [4]

In this question it is given that

Carla earns $8.43 per hour. It means that her hourly rate is $8.43 .

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First we have to understand what time and a half means .

Time and a half means 1.5 times of the normal rate. And to find the overtime pay, we have to multiply 1.5 and normal hourly rate. That is

=1.5*8.43 = $12.65

Therefore correct option is a .

4 0
3 years ago
Which of the following best explains the meaning of the equation?
Assoli18 [71]

Answer:

On a number line, negative five and positive five are the same distance from zero.

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Can anyone help me with this?<br><br> Reduce the fraction
Elden [556K]

\bf ~\hspace{7em}\textit{negative exponents} \\\\ a^{-n} \implies \cfrac{1}{a^n} ~\hspace{4.5em} a^n\implies \cfrac{1}{a^{-n}} ~\hspace{4.5em} \cfrac{a^n}{a^m}\implies a^na^{-m}\implies a^{n-m} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \cfrac{-20t^5u^2v^3}{48t^7u^4v}\implies \cfrac{-20}{48}\cdot \cfrac{t^5u^2v^3}{t^7u^4v^1}\implies \cfrac{-5}{12}\cdot \cfrac{v^3v^{-1}}{t^7t^{-5}u^4u^{-2}}\implies \cfrac{-5}{12}\cdot \cfrac{v^{3-1}}{t^{7-5}u^{4-2}} \\\\\\ \cfrac{-5}{12}\cdot \cfrac{v^2}{t^2u^2}\implies \cfrac{-5v^2}{12t^2 u^2}

3 0
3 years ago
What is the sum of the geometric series 2+6+18+...+486?
marin [14]

Answer:

728

Step-by-step explanation:

2+6+18+...+486

a=2

r=6/2=3

a_{n}=ar^{n-1}\\486=2(3)^{n-1}\\3^{n-1}=486/2=243=3^5\\n-1=5\\n=5+1=6\\S_{6}=2\frac{3^6-1}{3-1} \\=2\frac{729-1}{2}\\=728

6 0
3 years ago
There are nickles and quarters worth $2.20 in total. If there are 28 coins, how many nickels are there?
Eduardwww [97]
Answer:

There are 24 nickels

Step-by-step explanation:

Let x represent the number of nickels

Let y represent the number of quarters
—————————————————————

Value Value
Type Number of of
of of each all
Coin Coin Coin Coin
—————————————————————
Nickels | x | $0.05 | $0.05x
Quarters | y | $0.25 | $0.25y
—————————————————————
Totals 28 ——— $2.20
•••••••••••••••••••••••••••••••••••••••••••••••••

The first equation comes from the “Number of coins” column.

(Number of nickels) + (Number of quarters) = (total number of coins)

Equation: x + y = 28
—————————————————————
The second equation comes from the “value of all coins” column.

(Value of all nickels) + (Value of all quarters) = (Total value of all coins)

0.05x + 0.25y = 2.20

Remove the decimals by multiplying each term by 100:

5x + 25y = 220
—————————————————————
So we have the system of equations:

{x + y = 28
{5x + 25y = 202

Solve by substitution. Solve the first equation for y:

x + y = 28
y = 28 - x

Substitute (28 - x) for y in 5x + 25y = 220

5x + 25 (28 - x) = 220
5x + 700 - 25x = 220
-20x + 700 = 220
-20x = -480
x = 24

The number of nickels is 24.
————————————————————
Substitute in y = 28 - x
y = 28 - (24)
y = 4

The number of quarters is 4.
————————————————————
Checking:

24 nickels is $1.20 and 4 quarters is $1.00
That’s 28 coins.
Indeed $1.20 + $1.00 = $2.20
————————————————————

6 0
3 years ago
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