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svet-max [94.6K]
2 years ago
7

HELP PLEASE!! Write an equation in slope-intercept form for the line perpendicular to y=−4x+1 that passes through the point (−7,

1).
Mathematics
1 answer:
jekas [21]2 years ago
4 0

Answer:

slope intercept form is: y= mx +c

Step-by-step explanation:

Given : linear equation y = -4x + 1, the slope is m = -4

[you can read the slope m ,  from the equation]

rule for perpendicular slope: m1 x m2 = -1

Let the slope in the original equation equal m1, i.e. m1 = -4

therefore, -4 x m2 = -1

m2 = -1/-4

slope of perpendicular line = 1/4

so, y = 1/4 x + 1

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A

using the Cosine rule in ΔSTU

let t = SU, s = TU and u = ST, then

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substitute the appropriate values into the formula

t² = 5² + 9² - (2 × 5 × 9 × cos68° )

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3 years ago
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2 years ago
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2 years ago
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Bad White [126]
Answer a = 5 and b = 2.

Procedure

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2 years ago
511 = -7 (10x – 13)<br> steps
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Answer: x=-6

<u>Simplify both sides of the equation</u>

<u></u>511=(-7)(10x)+(-7)(-13)(Distribute)\\511=-70x+91<u></u>

<u></u>

<u>Flip the equation</u>

<u></u>-70x+91=511<u></u>

<u></u>

<u>Subtract 91 from both sides</u>

<u></u>-70x+91-91=511-91\\-70x=420<u></u>

<u></u>

<u>Divide both sides by -70</u>

<u></u>-70x/70=420/-70\\x=-6<u></u>

3 0
3 years ago
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