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Ludmilka [50]
3 years ago
14

What's simple random sampling? Is it possible to sample data instances using a distribution different from the uniform distribut

ion? If so, give an example of a probability distribution of the data instances that is different from uniform (i.e., equal probability).
Mathematics
1 answer:
topjm [15]3 years ago
4 0

Answer:

The answer is below

Step-by-step explanation:

The procedure of selecting a sample is thus called, fulfilling two fundamental properties:

-All individuals in the population have the same probability of being elected.

-All samples of the same size are equally likely.

From a mathematical point of view, simple random sampling is performed assuming that the population has infinite elements. In practice, it is often the case that the populations to be considered have a very large number of elements, which can be compared to a situation with infinite elements.

Yes, it is possible to sample data instances using a distribution different from the uniform distribution.

In excel, do the following to obtain a sample dataset.

E.g. to create a 5 element sample from the standard normal distribution, place the formula = NORM.S.INV (RAND ()) in cell A1, highlight the range A1: A15 and press Ctrl-D.

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What is 4^12 x 125^7? Express your answer in scientific notation
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How do you find the equation of a triangles altitude using point slope formula?
forsale [732]
<span><span><span>1. An altitude of a triangle is a line segment from a vertex perpendicular to the opposite side. Find the equations of the altitudes of the triangle with vertices (4, 5),(-4, 1) and (2, -5). Do this by solving a system of two of two of the altitude equations and showing that the intersection point also belongs to the third line. </span>
(Scroll Down for Answer!)</span><span>Answer by </span>jim_thompson5910(34047)   (Show Source):You can put this solution on YOUR website!
<span>If we plot the points and connect them, we get this triangle: 

 

Let point 
A=(xA,yA)
B=(xB,yB)
C=(xC,yC) 



------------------------------- 
Let's find the equation of the segment AB 


Start with the general formula 

 


Plug in the given points 

 


Simplify and combine like terms 

 


So the equation of the line through AB is  


------------------------------- 
Let's find the equation of the segment BC 


Start with the general formula 

 


Plug in the given points 

 


Simplify and combine like terms 

 


So the equation of the line through BC is  




------------------------------- 
Let's find the equation of the segment CA 


Start with the general formula 

 


Plug in the given points 

 


Simplify and combine like terms 

 


So the equation of the line through CA is  




So we have these equations of the lines that make up the triangle 


 



So to find the equation of the line that is perpendicular to  that goes through the point C(2,-5), simply negate and invert the slope  to get 

Now plug the slope and the point (2,-5) into  


 

 Solve for y and simplify 

So the altitude for vertex C is  



Now to find the equation of the line that is perpendicular to  that goes through the point A(4,5), simply negate and invert the slope to get  

Now plug the slope and the point (2,-5) into  


 

 Solve for y and simplify 

So the altitude for vertex A is  




Now to find the equation of the line that is perpendicular to  that goes through the point B(-4,1), simply negate and invert the slope to get  

Now plug the slope and the point (-4,1) into  


 

 Solve for y and simplify 

So the altitude for vertex B is  



------------------------------------------------------------ 
Now let's solve the system 


 

 Plug in  into the first equation 

 Add 2x to both sides and subtract 2 from both sides 

 Divide both sides by 3 to isolate x 


Now plug this into  

 

 



So the orthocenter is (-2/3,1/3) 

So if we plug in  into the third equation , we get 


 


 


 

 

So the orthocenter lies on the third altitude 





</span><span>
</span></span>
3 0
3 years ago
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