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Ludmilka [50]
3 years ago
14

What's simple random sampling? Is it possible to sample data instances using a distribution different from the uniform distribut

ion? If so, give an example of a probability distribution of the data instances that is different from uniform (i.e., equal probability).
Mathematics
1 answer:
topjm [15]3 years ago
4 0

Answer:

The answer is below

Step-by-step explanation:

The procedure of selecting a sample is thus called, fulfilling two fundamental properties:

-All individuals in the population have the same probability of being elected.

-All samples of the same size are equally likely.

From a mathematical point of view, simple random sampling is performed assuming that the population has infinite elements. In practice, it is often the case that the populations to be considered have a very large number of elements, which can be compared to a situation with infinite elements.

Yes, it is possible to sample data instances using a distribution different from the uniform distribution.

In excel, do the following to obtain a sample dataset.

E.g. to create a 5 element sample from the standard normal distribution, place the formula = NORM.S.INV (RAND ()) in cell A1, highlight the range A1: A15 and press Ctrl-D.

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Give the trig ratio as a fraction
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What is the question I understand the part where you need a ratio as a fraction but, is there a way you can put a pic of the numbers or put the numbers in the question?

7 0
3 years ago
What is 5x to the 6 power
stira [4]

Answer:

25-60+36

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
X/5=2/3=5/y<br><br> 2/3 <br> 4/9<br> 1
Mademuasel [1]
\frac{x}{5}= \frac{2}{3}  = \frac{5}{y}
Break the equation into parts;
\frac{x}{5} = \frac{2}{3} ;  \frac{2}{3}= \frac{5}{y}
Solving for x;
\frac{x}{5} = \frac{2}{3}
x=\frac{10}{3}
Solving for y;
\frac{2}{3} = \frac{5}{y} &#10;y= \frac{3*5}{2} &#10;y= \frac{15}{2}
\frac{x}{y} = \frac{10/3}{15/2}
\frac{x}{y} = \frac{4}{15}
5 0
3 years ago
Which pair of triangles is congruent?
stiv31 [10]

Answer:

The first pair.

Step-by-step explanation:

3 corresponding parts must be congruent for two triangles to be congruent. The first pair has 3 congruence markings; two angles and one side are congruent. Additionally, they are congruent by the ASA postulate because two angles and the included side are congruent.

7 0
3 years ago
Read 2 more answers
Simplify this expression
kompoz [17]
The first step for solving this problem is to know that in order to divide by a fraction,, we must multiply by the reciprocal of that fraction. This will look like the following:
\frac{x+2}{ x^{2} -6x-16} × 9x
Write -6x as a difference.
\frac{x+2}{ x^{2} +2x-8x-16} × 9x
Factor out x from x² + 2x.
\frac{x+2}{ x X (x+2)-8x-16} × 9x
Factor out -8 from -8(x + 2).
\frac{x+2}{ x X (x+2)-8(x+2)} × 9x
Factor out x + 2 from the denominator (bottom) of the expression.
\frac{x+2}{(x+2)X(x-8)} × 9x
Reduce the fraction with x + 2
\frac{1}{x-8} × 9x
Finally,, calculate the product to find your final answer.
\frac{9x}{x-8}
This means that the correct answer to your question is going to be option B.
Let me know if you have any further questions.
:)
3 0
3 years ago
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