Are you trying to simplify the equation? if so, combine the like terms on each side first. -3x + 3 = -2 + 2x. Then simplify, -5x = -5. And solve, x = 1
Answer:
B. zero
Step-by-step explanation:
If the temperature is supposed to remain constant over time (the same) when working properly, then this means that there is no increase or decrease over time.
If there were a line to represent this, then it would be a straight line with a slope of 0 because the temperature would remain the same.
So if u were to use a calculator, which you probably might need, you would take the radius, square it by 3, multiply by 4 and then divide by 3.
If

represent a family of surfaces for different values of the constant

. The gradient of the function

defined as

is a vector normal to the surface

.
Given <span>the paraboloid

.
We can rewrite it as a scalar value function f as follows:

The normal to the </span><span>paraboloid at any point is given by:

Also, the normal to the given plane

is given by:

Equating the two normal vectors, we have:
</span>

Since, -1 = 2 is not possible, therefore
there exist no such point <span>
on the paraboloid
such that the tangent plane is parallel to the plane 3x + 2y + 7z = 2</span>
.
Answer:
1 is C and 2 is B
Step-by-step explanation: