Question

Please answer!!!!!!!!!!!

Answer 1

For this case we have a function of the form $y = f (x).$ Where:

$f (x)=\frac {3 + x}{x-3}$

We must find the value of the function when $x = a + 2$

So, substituting the value of "x" we have:

$f (a + 2) = \frac {3+ (a + 2)} {(a + 2) -3}$

$f (a + 2) = \frac {3 + a + 2} {a + 2-3}$

$f (a + 2)=\frac {5 + a} {a-1}$

Answer:

$f(a + 2) =\frac {5 + a} {a-1}$

Option C

Answer 2

Answer:

C.   $f(a + 2) = \dfrac{5 + a}{a - 1}$

Step-by-step explanation:

Replace x with a + 2 and simplify the expression.

$f(x) = \dfrac{3 + x}{x - 3}$

Let x = a + 2

$f(a + 2) = \dfrac{3 + a + 2}{a + 2 - 3}$

$f(a + 2) = \dfrac{5 + a}{a - 1}$