Answer:
Step-by-step explanation:
The funtion is:
C(p)= 3(p)+1.07 (1)
where: 3 is the package cost, p is the number of packages and 1.07 is the taxes
the cost could be equal or less than the gift card value so:
C
(2)
Replace 2 en 1
x 1.07
3(p)
![3p [tex]\leq](https://tex.z-dn.net/?f=3p%20%5Btex%5D%5Cleq)
14.02\\\\p\leq \frac{14.02}{3} \\\\p\leq 4.67[/tex]
It´s important to aprox the quantity to the minimum value so I can buy 4 packages
The reasonable domain is for all R because any number is a possible value of the independent variable
4t=r
a=pir^2
sub 4t for r
a=pi(4t)^2
a=pi16t^2
a(t)=16pi(t^2)
A. a(t)=16pi(t^2)
B. sub 4 for t
a(4)=16pi4^2
a(4)=16pi16
a(4)=16*16*3.14
a(4)=803.84 square units
A. a(t)=16pi(t^2)
B. 803.84 square units
Answer:
Step-by-step explanation:
Answer:
C choice.
Step-by-step explanation:
First, we move the same terms to the same side.
Then we move 6 to divide - 18.
Answer (13 of the original arrangements are duplicates now, as
AAAF F F FDDDDCC, AAF F F FDDDDCCA, ..., CAAAF F F FDDDDC
are identical): 900900/13 = 69300.
