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3 years ago

How would I set up this equation? Thank you

Mathematics

1 answer:

algol [13]3 years ago

5 0

Y + 2 = x, or y + 12 = 2x

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Two consecutive negative integers have a product of 2. what are the integers ?

MrRissso [65]

product is multiplication

2 negative numbers multiplied by each other equal 2

since it is multiplication the numbers would need to be 2 or less

therefore the 2 numbers are -1 and -2

-1 * -2 = 2

6 0

4 years ago

Find an explicit rule for the nth term of the sequence.The second and fifth terms of a geometric sequence are 18 and 144, respec

vova2212 [387]

Given:

second term = 18

fifth term = 144

The nth term of a geometric sequence is:

$\begin{gathered} a_n\text{ = ar}^{n-1} \\ Where\text{ a is the first term} \\ r\text{ is the common ratio} \end{gathered}$

Hence, we have:

$\begin{gathered} \text{ar}^{2-1}\text{ = 18} \\ ar\text{ = 18} \\ \\ ar^{5-1}=\text{ 144} \\ ar^4\text{ =144} \end{gathered}$

Divide the expression for the fifth term by the expression for the second term:

$\begin{gathered} \frac{ar^4}{ar}\text{ = }\frac{144}{18} \\ r^3\text{ = }\frac{144}{18} \\ r\text{ = 2} \end{gathered}$

Substituting the value of r into any of the expression:

$\begin{gathered} ar\text{ = 18} \\ a\text{ }\times\text{ 2 = 18} \\ Divide\text{ both sides by 2} \\ \frac{2a}{2}\text{ =}\frac{18}{2} \\ a\text{ = 9} \end{gathered}$

Hence, the explicit rule for the sequence is:

$a_n\text{ = 9\lparen2\rparen}^{n-1}$

5 0

1 year ago

Please answer this qwq

balu736 [363]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

Triangles A and B are similar. A has side lengths 2, 4, and 6. B has corresponding side lengths ???, 16, and 24

ZanzabumX [31]

Answer:

The length of A will be 8 as

The ratio between the sides are 4:1

Since Side is 2 therefore side A=2*4

Hope u got your answer..

8 0

3 years ago

Arithmetic and geometric series -Find the sum of the first 50 terms of the following series, to the nearest integer.

grandymaker [24]

Answer:

Step-by-step explanation:

21-13=8 and 29-21=8

So this is aritmetic series where a₁ = 13, and r = 8

Sum of the first n terms:

$S_n=\dfrac{a_1+a_n}{2}\cdot n=\dfrac{a_1+a_1+(n-1)r}{2}\cdot n=\dfrac{2a_1+(n-1)r}{2}\cdot n\\\\\\S_{50}=\dfrac{2\cdot13+(50-1)\cdot8}{2}\cdot50=(13+49\cdot4)\cdot 50=10,450$

5 0

3 years ago