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2 years ago

What number is 5he same ratio to 64 as 5 is to 8

Mathematics

1 answer:

frosja888 [35]2 years ago

4 0

Answer:

Answer is 24 and 40.

Step-by-step explanation:

I'm not quite sure if i'm wrong i'm terribly sorry :(

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Jada and Lin are comparing inches and feet. Jada says that the constant of proportionality is 12. Lin says it is 1/12 Do you agr

irinina [24]

Answer: Look up your exact question

Step-by-step explanation: The question you've asked has also been asked by another person on brainly, you could look at their answer. Link: brainly.com/question/11191408

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3 years ago

What is the area of the following circle?

satela [25.4K]

Answer:

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8 0

3 years ago

There are 2.54 centimeters in 1 inch. There are 100 centimeters in 1 meter.

Alika [10]

Answer:

5 meters

Step-by-step explanation:

If in 1 inch have 2.54 centimeters, in 197 inches will have:

197×2.54 = 500.38 centimeters

If 100 centimeters are 1 meter, 500 centimeters will have 5 meters, so 197 inches have 5 meters

3 0

3 years ago

What is the solution to the proportion? 5/8 = m/40

Triss [41]

Your answer is 25. You do 40 times 5 divided by 8 or 8 times 5 is 40 and 5 times 5 is 25. Hope this helps

4 0

3 years ago

Read 2 more answers

Please hepl with math

Ivenika [448]

Answer:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

Step-by-step explanation:

We are given the expression to be simplified:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}}$

Let us take common a term with a power of 5 from the numerator and the denominator of the given expression.

We know that:

$a^{p+q} = a^p \times a^q$

Let us use it to solve the powers of 5 in the given expression.

$\therefore$ we can write:

$5^{n+2} = 5^{n+1}\times 5= 5^n\times 5^{2}$

$5^{n+1} = 5^n\times 5$

The given expression becomes:

$\dfrac{5^{n+1} \times 5-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n}\times 5}$

Taking common $5^{n+1}$ from the numerator and

Taking common $5^{n}$ from the denominator

$\Rightarrow \dfrac{5^{n+1} (5-6)} {5^{n}(13-2\times5)}\\\Rightarrow \dfrac{5^{n+1} (-1)} {5^{n}(13-10)}\\\Rightarrow -\dfrac{5^{n+1}} {5^{n}\times3}\\\Rightarrow -\dfrac{5^{n}\times 5} {5^{n}\times3}\\\Rightarrow -\dfrac{5}{3}$

$\therefore$ The answer is:

$\dfrac{5^{n+2}-6\times 5^{n+1}}{13 \times5^{n}-2\times5^{n+1}} = -\dfrac{5}{3}$

6 0

3 years ago