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vesna_86 [32]
3 years ago
10

Write the equation of a line that is

Mathematics
2 answers:
siniylev [52]3 years ago
6 0
Your answer would be “y=-8”
Mila [183]3 years ago
5 0

Answer:

y = -8

Step-by-step explanation:

Since the line is parallel to y=9, which is a horizontal line, the slope will be 0.

Using the equation y - y1 = m(x-x1), we'll plug in the numbers m = 0, y1 = -8, and x = 3.

y + 8 = 0(x - 3)

y = -8

The equation of the line is y = -8.

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What is the value of the 3rd iterate if x0 = 2.4 Carry out your answers to the 5th decimal place
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Answer:

I think it's 2.45111

Step-by-step explanation:

4 0
2 years ago
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DJ Mykel is making a playlist for a radio show; he is trying to decide what 14 songs to play and in what order they should be pl
konstantin123 [22]

Answer:

5878600 different playlists.

Step-by-step explanation:

Since we require 14 songs for the playlist and there are 7 hip-hop, 5 jazz, 7 pop, and 8 blues songs, and DJ Mykel wants to play no more than 3 hip-hop songs, the number of ways in which he can combine the 7 hip-hop songs to play no more than 3 is ⁷C₃ = 7!/4!3!.

Now, since we have 3 songs already selected, we are left with 14 - 3 = 11 songs to select.

Since we have selected the 3 hip-hop songs, we are left with 5 jazz, 7 pop, and 8 blues songs which sum to a total of 20 songs.

So, we have 20 songs to select in 11 ways which is ²⁰C₁₁ = 20!/(20 - 11)!11! = 20!/9!11!

So, the number of different playlists that can be formed is thus

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8 0
3 years ago
So,some please help me with this question !
Tamiku [17]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

\qquad❖ \:  \sf   \: \angle C  = 63 \degree

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:x + 4x  + 12 + x=180°

( Angle EBA= Angle DBC, and the three angles sum upto 180° due to linear pair property )

\qquad❖ \:  \sf \:6x + 12 = 180

\qquad❖ \:  \sf \:6x = 180 - 12

\qquad❖ \:  \sf \:6x = 168

\qquad❖ \:  \sf \:x = 28 \degree

Next,

\qquad❖ \:  \sf   \: \angle C + \angle D + x = 180°

\qquad❖ \:  \sf   \: \angle C +3x + 5  + x = 180°

\qquad❖ \:  \sf   \: \angle C +4x  = 180 - 5

\qquad❖ \:  \sf   \: \angle C +4(28)  = 175

( x = 28° )

\qquad❖ \:  \sf   \: \angle C +112  = 175

\qquad❖ \:  \sf   \: \angle C  = 175 - 112

\qquad❖ \:  \sf   \: \angle C  = 63 \degree

\qquad \large \sf {Conclusion}  :

\qquad❖ \:  \sf   \: \angle C  = 63 \degree

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