3 years ago

A merry go round revolves 2 times per minute, jack is 10 feet from the center while bob is 14 feet from the center

Mathematics

1 answer:

Nesterboy [21]3 years ago

5 0

Answer:

Jack's linear speed is 126ft/min

Bob's linear speed is 176ft/min

Step-by-step explanation:

First of all, find the circumference of both circles given the radius; Jack, 2pir (10)=63ft. Bob 2pir(14)=88ft. Now, realize that the merry go round revolves 2 times per min; 2rpm, so multiply each result by 2 and there you go.

You might be interested in

A rectangular room is 3 meters longer than it is wide, and its perimeter is 26 meters. Find the dimension of the room. The lengt

Juli2301 [7.4K]

Perimeter is the sum of all 4 walls.

Divide the perimeter in half for the total of the width + the length:

26/2 = 13 meters

Subtract the difference in length:

13 - 3 = 10

Divide by 2 walls:

10/2 = 5

The width is 5 metes.

The length is the 5 metes + the 3 meter difference = 5 +3 = 8 meters.

The length is 8 meters and the width is 5 meters.

5 0

3 years ago

The sum of the digits of a two digit number is 11. The tens digit is one less than three times the ones digit. Find the original

aniked [119]

Answer:

9+2

Step-by-step explanation:

8 0

4 years ago

Simplify \frac{4(3x^{2}y^{4})^{3}}{(2x^{3}y^{5})^{4}} Show your work.

irina1246 [14]

$\frac{4(3x^{2}y^{4})^{3}}{(2x^{3}y^{5})^{4}} = \frac{4* ( 3^{3} x^{6} y^{12}) }{2^4 x^{12} y^{20}} = \frac{108}{16x^{6} y^{8} } = \frac{27}{4 x^{6} y^{8} }$