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3 years ago

12

Simplify \frac{4(3x^{2}y^{4})^{3}}{(2x^{3}y^{5})^{4}} Show your work.

1 answer:

irina1246 [14]3 years ago

4 0

$\frac{4(3x^{2}y^{4})^{3}}{(2x^{3}y^{5})^{4}} = \frac{4* ( 3^{3} x^{6} y^{12}) }{2^4 x^{12} y^{20}} = \frac{108}{16x^{6} y^{8} } = \frac{27}{4 x^{6} y^{8} }$

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357 mi²

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3 years ago

Determine whether the quadrilateral is a parallelogram using the indicated method Q(-10,-2), R(1,-1), S(1,-7), T(-11,-8) (Distan

myrzilka [38]

Answer:

The quadrilateral is not a parallelogram

Step-by-step explanation:

we know that

In a parallelogram opposite sides are parallel and congruent

Find the length of the sides of the quadrilateral

step 1

Find the distance QR

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

Q(-10,-2), R(1,-1)

substitute

$d=\sqrt{(-1+2)^{2}+(1+10)^{2}}$

$d=\sqrt{(1)^{2}+(11)^{2}}$

$d=\sqrt{122}\ units$

step 2

Find the distance TS

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

T(-11,-8), S(1,-7)

substitute

$d=\sqrt{(-7+8)^{2}+(1+11)^{2}}$

$d=\sqrt{(1)^{2}+(12)^{2}}$

$d=\sqrt{145}\ units$

we have that

QR and TS are opposite sides

In a parallelogram opposite sides are congruent but in this problem

$QR \neq TS$

$\sqrt{122}\ units \neq \sqrt{145}\ units$

therefore

The quadrilateral is not a parallelogram

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4 years ago