A quadrilateral has 4 vertices and the sum of the measures of the interior angles is 360 degrees. There cannot be 4 diagonals in a quadrilateral.
Well the formula is : b1+b2/2 (h)
so the height would be solved as :
13.5 = 3+6/2 (h)
13.5 = 9/2 (h)
h = (13.5)/(9/2)
h = (13.5) x (2/9) *reciprocal*
h = (27) / (9)
h = 3
add all the angles and make them equal to 360
88 + 108 + (3x-6) + 2x = 360
196 + 5x -6 = 360
190 + 5x = 360
5x = 170
x = 34 = answer
Answer:
see below
Step-by-step explanation:
We can use point slope form
y - y1 = m(x-x1)
where m is the slope and ( x1,y1) is a point on the line
y-12 = 3(x-12)
If we want it in slope intercept form
Distribute
y-12 = 3x-36
Add 12 to each side
y-12+12 = 3x-36+12
y = 3x-24
