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nikklg [1K]
3 years ago
7

Dan drove 845 miles in 13 hours. At the same rate, how many miles would he drive in 11 hours

Mathematics
1 answer:
denis23 [38]3 years ago
6 0
845 miles / 13 hours = 65 miles per hour

65 miles per hour x 11 hours = 715 miles
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If (2i/2+i)-(3i/3+i)=a+bi, then a=<br>A. 1/10<br>B. -10<br>C. 1/50<br>D. -1/10​
Verizon [17]

Answer:

Option A is correct.

Step-by-step explanation:

We are given:

\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi

We need to find the value of a.

The LCM of (2+i) and (3+i)  is (2+i)(3+i)

=\frac{2i(3+i)}{(2+i)(3+i)}-\frac{3i(2+i)}{(2+i)(3+i)}\\=\frac{6i+2i^2}{(2+i)(3+i)}-\frac{6i+3i^2}{(2+i)(3+i)}\\=\frac{6i+2i^2-(6i+3i^2)}{(2+i)(3+i)}\\=\frac{6i+2i^2-6i-3i^2)}{5+5i}\\=\frac{-i^2}{5+5i}\\i^2=-1\\=\frac{-(-1)}{5+5i}\\=\frac{1}{5+5i}

Now rationalize the denominator by multiplying by 5-5i/5-5i

=\frac{1}{5+5i}*\frac{5-5i}{5-5i} \\=\frac{5-5i}{(5+5i)(5-5i)}\\=\frac{5-5i}{(5+5i)(5-5i)}\\(a+b)(a-b)= a^2-b^2\\=\frac{5(1-i)}{(5)^2-(5i)^2}\\=\frac{5(1-i)}{25+25}\\=\frac{5(1-i)}{50}\\=\frac{1-i}{10}\\=\frac{1}{10}-\frac{i}{10}

We are given

\frac{2i}{2+i}-\frac{3i}{3+i} = a+bi

Now after solving we have:

\frac{1}{10}-\frac{i}{10}=a+bi

So value of a = 1/10 and value of b = -1/10

So, Option A is correct.

8 0
3 years ago
Given the Trapezoid ABCD<br><br> Find the length of AD <br><br> Pls hellpppp
matrenka [14]

Given:

In trapezoid ABCD, AD\parallel BC, MN is the mid-segment of ABCD, AD=30x-10,MN=31x+1,BC=30x+28.

To find:

The length of AD.

Solution:

We know that the length of the mid-segment of a trapezoids is half of the sum of lengths of two parallel sides of the trapezoid.

In trapezoid ABCD,

MN=\dfrac{AD+BC}{2}

31x+1=\dfrac{30x-10+30x+28}{2}

31x+1=\dfrac{60x+18}{2}

31x+1=30x+9

Isolate variable terms.

31x-30x=9-1

x=8

Now,

AD=30x-10

AD=30(8)-10

AD=240-10

AD=230

Therefore, the length of AD is 230.

6 0
2 years ago
PLEASE HELP SOLVE! FIRST TO SOLVE RIGHT WILL GET BRAINIEST
IrinaVladis [17]

Answer:

  40π/3 cm^2

Step-by-step explanation:

The centerline of the shaded region has a radius of 3 +4/2 = 5 cm. Its length is 1/3 of a circle with that radius, so is ...

  length of centerline = (1/3)(2π·5 cm) = (10/3)π cm

The shaded region is 4 cm wide, so the area is the product of that width and the centerline length:

  (4 cm)(10/3 π cm) = 40π/3 cm^2

3 0
3 years ago
The perimeter of a rectangle garden is 54yd. One side has a length of 15 yd. Find the area of the garden.
Lelechka [254]

Answer:

=》Area = 180 sq.yd

Step-by-step explanation:

perimeter = 2l + 2b

where, we have l = 15

  • so (2×15) + 2b = 54
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  • 2b = 24
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now, Area = l × b = 12 × 15 = 180 sq.yd

5 0
2 years ago
Read 2 more answers
Steven's family traveled 7/10 of the distance to his aunt’s house on Saturday. They traveled 2/3 of the remaining distance on Su
oksano4ka [1.4K]

Answer:

Step-by-step explanation:

Answer: 1/5 of the total distance to his grandmothers house was traveled on Sunday

The total distance to to his grandmothers house is assumed to be 1

Marks family traveled 7/10 of the distance to his grandmothers house on Saturday. The remaining distance would

1 - 7/10 = 3 /10

They traveled 2/3 of the remaining distance on Sunday. This means that the distance that they travelled on Sunday is

2/3 × 3/10 = 2/10 = 1/5

5 0
1 year ago
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