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aleksley [76]
3 years ago
10

What is the LCM of 37 and 12?

Mathematics
1 answer:
artcher [175]3 years ago
6 0
37|37 \\ 1 \\ \\ 12|2 \\ 6 \ |2 \\ 3 \ |3 \\ 1 \\ \\ 12=2^2*3 \\ \\ L.C.M(37;12)=444
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What is the length of the diagonal of a rectangle that is 12 inches long and 6 inches wide?​
lakkis [162]
To find the diagonal of the rectangle we have to use Pythagorean theorem!

Pythagorean theorem is used to find the length of a missing angle such as the hypotenuse or the sides a and b.

Steps to solve:

1. 12 in is the length or the base of the right triangle, and 6 in is the wide or the side a.
2. Now use the formula: a^2+b^2=c^2, and plug in the numbers!
3. 6^2+12^2=c^2, now just solve the squared numbers.
4. 36+144=c^2
5. 180=c^2
6. Find the square root of 180.

And that is you answer!
If helped mark me the brainiest!!
4 0
3 years ago
What is bed? because I need help I don't know what the answer is
Allisa [31]

62 +62 = 124

360 - 124 = 176

176/2 = 88

BED = 88 degrees

6 0
3 years ago
For the graph, what is a reasonable constraint so that the function is at least 300?
blsea [12.9K]

Answer:

C) 0 ≤ x ≤ 25

Step-by-step explanation:

We are supposed to find a reasonable constraint so that the function is at least 300 i.e. the value of x at which f(x) is greater or equal to 300

A)x ≥ 0

Refer the graph

At x = 0

f(x)=300

On increasing the value of x , f(x) increases but at x = 12 it starts decreasing

So, x ≥ 0 can also have f(x)<300

So, Option A is wrong

B)−5 ≤ x ≤ 30

At x = -5

f(x) = 100

So, Option B is wrong since we require f(x) is greater or equal to 300

c)0 ≤ x ≤ 25

At x = 0

f(x)=300

At x = 12 , it starts decreasing

At x = 25

f(x)=300

So, The value of f(x) is at least 300 when 0 ≤ x ≤ 25

D)All real numbers

At x = 30

f(x)=0

But we require f(x) greater or equal to 300

Hence Option C is true

8 0
3 years ago
Help me please and explain. <br><br>FIND THE AREA OF THE UNSHADED REGION ​
bagirrra123 [75]

To solve this first find the area of each of the white shapes inside the rectangle

The formula for the area of a circle is:

A = πr²

In this case we know that the radius is 2

Plug what you know into the area of a circle formula:

A = π2²

A = π4

A = 4π

A ≈ 12.57

The formula for the area of a square is:

A = Length x Height

In this case we know that both length and height are 3

Plug what you know into the formula for area of a square:

A = 3 x 3

A = 9

To find the area of the UNSHADED region simply add together the area of the circle (12.57) with the area of the square (9):

12.57 + 9 ≈ 21.57

To find the area of the SHADED region find the total area of the surrounding rectangle then subtract the area of unshaded area from the total area of the surrounding rectangle.

The formula for the area of a rectangle is:

A = Length x Height

The length is 10 and the height is 7

A = 10 x 7

A = 70

Shaded region:

70 - 21.57 = 48.43

Unshaded region: 21.57

Total area of surrounding rectangle: 70

Shaded region: 48.43

Hope this helped!

~Just a girl in love with Shawn Mendes

5 0
3 years ago
Read 2 more answers
It costs $200.00 to rent the mini-golf course, plus $7.25 per person. What would be the total cos
igor_vitrenko [27]

$417.50 should be the correct answer you just multiply  the $7.25 to 30 and then add the $200.

7 0
3 years ago
Read 2 more answers
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