Answer:
Given that Angelo spends the same amount every day from the amount in
the lunch card, the function of the amount remaining is a linear function.
The constant rate of change of the function is; -5.25
The two ordered pairs used to find the constant rate of change are; (1, 44.75) and (2, 39.5)
Reasons:
The amount Angelo's mother put on the lunch card = $50
A possible table of values to the question is presented as follows;
Required:
The constant rate of the function that gives the amount remaining from the
amount Angelo's mother put on his lunch card.
Solution:
The two ordered pairs that can be used to find the slope or constant rate of change are;
(x₁, y₁) = (1, 44.75), and (x₂, y₂) = (2, 39.5)
With the above two ordered pairs, we have the constant rate of change of the function given as follows;
The constant rate of change for the function that gives the amount remaining in the lunch card is; -5.25
Answer:
Mean: 5.041
Median:5.8
Mode: 6.5, appeared 2 times
Range: 5.8
Step-by-step explanation:
Answer:
It is already simplified
Step-by-step explanation:
0.09375 in decimals
<h3>
Answer: 7/10</h3>
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Explanation:
There are 30 days in April. Since it rained 9 of those days, the empirical probability of it raining in April is 9/30 = (3*3)/(3*10) = 3/10.
If we assume that the same conditions (ie weather patterns) hold for May, then the empirical probability of it raining in May is also 3/10. By "raining in May", I mean specifically raining on a certain day of that month.
The empirical probability of it not raining on the first of May is therefore...
1 - (probability it rains)
1 - (3/10)
(10/10) - (3/10)
(10-3)/10
7/10
We can think of it like if we had a 10 day period, and 3 of those days it rains while the remaining 7 it does not rain.
