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Ira Lisetskai [31]
3 years ago
15

A sequence is defined recursively by the formula f(n+1) =f(n) + 3 the first term of the sequences is -4 what is the next term in

the sequence
Mathematics
1 answer:
MArishka [77]3 years ago
8 0
-1 would be your answer. f(0) = -4. f(1) = f(0)+3 so f(1) = -1
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PLEASE HELPPPPP!!!!!!!!! (show work if you can)
Kryger [21]

Answer:

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Step-by-step explanation:

Start by finding the LCM of the coefficients of each polynomial:

LCM(12,18,30)=180

Next, to find the least common multiple of each of the following terms, we need to take the absolute minimum we can of each term (x, y, and z). The largest term of x is x^4 in the first polynomial, so we'll take exactly that for our x term in the LCM, absolutely nothing more. Similarly, the largest term of y in any of the three polynomials is y^3 (also in the first polynomial) and the largest z term in any of the three polynomials is z^2 in the second polynomial. Thus, the LCM of all our polynomials is:

180\cdot x^4\cdot y^3\cdot z^2=\boxed{180x^4y^3z^2}

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3 years ago
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To two decimal places, find the value of k that will make the function f(x) continuous everywhere. f of x equals the quantity 3x
Fiesta28 [93]

Given function is

f(x)=\left\{\begin{matrix}3x+k & x\leq -4 \\ kx^2-5 & x> -4\end{matrix}\right.

now we need to find the value of k such that function f(x) continuous everywhere.

We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.

So we just need to find both left and right hand limits then set equal to each other to find the value of k

To find the left hand limit (LHD) we plug x=-4 into 3x+k

so LHD= 3(-4)+k

To find the Right hand limit (RHD) we plug x=-4 into

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so RHD= k(-4)^2-5

Now set both equal

k(-4)^2-5=3(-4)+k

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16k-k=-12+5

15k=-7

k=-\frac{7}{15}

k=-0.47

<u>Hence final answer is -0.47.</u>




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Answer:

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Step-by-step explanation:

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