see the attached figure to better understand the problem
Let
2L---------> lenght side of hexagon
we know that
in one of those triangles
sin 30=1/2
sin 30=L/hypotenuse
solve for L
L=hypotenuse*sin 30-------->L=( 1 8 √ 3 )*(1 /2)------> L=9√3 units
Find the perimeter
perimeter=(2L)*6--------> L*12-------> Perimeter=9√3*12--------->108√3 units
therefore
the answer is
the perimeter of the regular hexagon is 108√3 units
