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lakkis [162]
3 years ago
11

You run 7 miles in one hour and 21 miles in three hours

Mathematics
2 answers:
OlgaM077 [116]3 years ago
7 0

Your answer will be 3

julia-pushkina [17]3 years ago
4 0

Answer: the answer is three sorry if its wrong.

Step-by-step explanation:

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1*5*665*5665*5545*5665
sergiy2304 [10]

Answer:

thats long just use calcukator

5 0
3 years ago
Which of the following statements are true about scalar multiplication of matrices?
Greeley [361]

Scalar multiplication of a matrix refers to the multiplication of all the elements of the matrix by an ordinary number which is called a scalar.

From the given options the statements which are true about scalar multiplication of matrices are;

a)       You can multiply a matrix of any size by a scalar.

b)      For any matrix A, 1 × A = A.

c)       Scalar multiplication is a shortcut for repeated addition of the same matrix.

3 0
3 years ago
Read 2 more answers
What is the G.C.F of 36 and 18? *
sdas [7]

<em>Hope</em><em> </em><em>this</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em><em>:</em><em>)</em>

5 0
3 years ago
Read 2 more answers
The value of which of these expressions is closest to e?
mars1129 [50]

Answer:

B.

Step-by-step explanation:

Given: expressions

To find: the expression whose value is closest to e

Solution:

Value of e is 2.718

\left ( 1+\frac{1}{19} \right )^{19}=\left ( \frac{20}{19} \right )^{19}=2.65\\\left ( 1+\frac{1}{22} \right )^{22}=\left ( \frac{23}{22} \right )^{22}=2.659\\\left ( 1+\frac{1}{20} \right )^{20}=\left ( \frac{21}{20} \right )^{20}=2.653\\\left ( 1+\frac{1}{21} \right )^{21}=\left ( \frac{22}{21} \right )^{21}=2.656

Therefore, value 2.659 is closest to the value of e.

So, option B. is correct.

7 0
3 years ago
a trapezoid has parallel sides of length 26 mm and 44 mm. its other sides measure 10 mm and 17 mm. what is the length of the bim
kirill115 [55]

Answer:

35 mm.

Step-by-step explanation:

That would be (26 + 44)/2

= 70/2

= 35 mm.

5 0
3 years ago
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