Question

In a basket, there are 7 male kittens and 5 female kittens. Donna randomly selects one, puts it back, and then randomly selects another. What is the probability that both selections were female kittens?

Answer 1

We are given that

number of male kittens =7

number of female kittens =5

total number of kittens = number of male kittens + number of female kittens

total number of kittens = 7+5

total number of kittens = 12

now, we can find probability of selecting female kittens

P(female kittens)=(number of female kittens)/( total number of kittens)

P(female kittens) is

$=\frac{5}{12}$

now, we are given that

Donna randomly selects one, puts it back, and then randomly selects another

so, both probability are independent

so,

the probability that both selections were female kittens is

=P(female kittens)*P(female kittens)

now, we can plug values

the probability that both selections were female kittens is

$=\frac{5}{12}\times \frac{5}{12}$

$=\frac{25}{144}$...............Answer