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Inessa [10]
3 years ago
14

You were preparing the slides and accidentally spilled some broth inoculated with unknown but potentially highly pathogenic bact

eria over the table. Your partner did not notice that and put the marker on that spot while labeling the slides. Then he passed marker to the other working pair of students. Everybody routinely washed their hands with regular soap by the end of the lab and left home.
How many direct and indirect transmission episodes could you expect after all?
A. 1 direct and 3 indirect transmissions
B. 1 direct and 2 indirect transmissions
C. 3 indirect transmissions
D. Unknown number of direct and indirect transmissions
Biology
1 answer:
Inessa [10]3 years ago
4 0

Answer:

C. 3 indirect transmissions

Explanation:

In epidemiology, direct transmission is considered to occur when an individual has direct contact with a pathogen, which infects him and develops a disease. Indirect infections, on the other hand, occur when individuals come into contact with the pathogen through a transmission vehicle.

In this case, we can conclude that in the question above, there were 3 cases of indirect transmission. This is because all people who had contact with the pathogen, established that contact through the contaminated marker. In this case, the marker is a transmission vehicle.

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There are four bases found in DNA: adenine (A), cytosine (C), guanine (G), and thymine (T). Adenine forms a base pair with thymine, and cytosine forms a base pair with guanine. There is a one-to-one relationship in these base pairings (Chargaff’s rule), which means that if you know the percentage of any one of them within a given DNA sample, you can calculate the percentages of the other three. In this case, you're given the percentage of guanine, and you want to find out the percentage of adenine.

Since guanine base-pairs with cytosine and since there must be as much cytosine as there is guanine, 41% of the bases in this gene are cytosine as well. That means that adenine and thymine <em>together </em>make up the remaining 18% (100% − 41% G − 41% C) of the base pairs. If there must be an equivalence in the number of thymine and adenine bases per Chargaff's rule, then half of the remaining base pairs must comprise adenine and the other half comprise thymine. Half of 18% is 9%.

Thus, adenine makes up 9% of the bases in this gene.

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