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zhannawk [14.2K]
3 years ago
6

Refer the diagram at the right. identify each angle pair as adjacent, vertical, or neither 7-12

Mathematics
1 answer:
Oxana [17]3 years ago
8 0
Adjacent angles are angles that are side by side (right next to each other).  They share a side.  #7 and 11 are pairs of adjacent angles.

Vertical angles are angles that are directly across from each other.  They are the same angle.  #8 and 9 are vertical angles.

#10 and 12 do not fit either of these descriptions so they are neither.
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HELP plsss if I don’t answer this I can’t go to lunch
zhannawk [14.2K]
7/g This is the correct answer to your problem
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The scatter plot below shows a linear association. Which is the best linear model for the data?
Ivanshal [37]

Answer:

ye its y=5x-10

Step-by-step explanation:

7 0
3 years ago
80 POINTS HELP<br> 1. What is the value of x? Show all of your work.
AnnyKZ [126]

Answer:

x = 9cm

Step-by-step explanation:

This is a right triangle so we can use the Pythagorean theorem

a^2 + b^2 = c^2  where a and b are the legs and c is the hypotenuse

6^2 + x^2 = ( sqrt(117) ^2)

36 + x^2 = 117

Subtract 36 from each side

x^2 = 117 -36

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6 0
3 years ago
Read 2 more answers
HELP PLEASE WILL GIVE BRAINLIEST
abruzzese [7]
Answer:
$1.21

Explanation:
What we know:
- $5.88=3 pounds of apples
- price went up by $0.75 per pound

First, we divide $5.88 by 3 to find out how much one pound of apples cost.

5.88/3
=1.96

Therefore, the new price of apples per pound is $1.96.

Because the old price of apples per pound was $0.75 cheaper, we subtract 0.75 from 1.96.

1.96-0.75
=1.21

Therefore, the old price of apples per pound was $1.21.

I hope this helps! Please comment if you have any questions.
7 0
3 years ago
Read 2 more answers
Seven pieces of rope have an average (arithmetic mean) length of 68 centimeters and a median length of 84 centimeters. If the le
Svet_ta [14]

Answer:

The maximum possible length, in centimeters, of the longest piece of rope is 134 cm

Step-by-step explanation:

Let the seven pieces be a,b,c,d,e,f,g

Average of 7 pieces of ropes  =68

Average = \frac{\text{Sum of all lengths}}{\text{No. of pieces}}

68= \frac{\text{Sum of all lengths}}{7}

68 \times 7 =\text{a+b+c+d+e+f+g}

476=\text{a+b+c+d+e+f+g} --A

We are given that the median length of a piece of rope is 84 centimeters.

We arrange the pieces in the ascending order

So, median will be the length of 4th piece

So, d = 84 cm

the length of piece a,b,c will be less than 84 and the value of e,f,g must be greater than or equal to 84

Let us suppose the length of a,b,c be x

Let us suppose the length of e,f be 84

The length of the longest piece of rope is 14 centimeters more than 4 times the length of the shortest piece of rope

So, g = 4x+14

Substitute the value in A

476=x+x+x+84+84+84+4x+14

476=7x+266

\frac{476-266}{7}=x

30=x

g = 4x+14=4(30)+14=134

Hence the maximum possible length, in centimeters, of the longest piece of rope is 134 cm

7 0
3 years ago
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