First put in ascending order.
0, 2, 2, 4, 5, 6, 7
The median is the middle number: 4
The mode is the number that repeats the most often: 2
The mean is the average. Add the numbers and divide by 7.
26/7 = 3.71
By using Nathan's expression, Mitchel should have received 2 1/4 pounds of lemon drops. By using Darren's expression, Mitchel should have received 2 1/4 pounds of lemon drops. The difference in the amount of lemon drops Mitchel should have received using Nathan's expression instead of Darren's expression is 0 pounds.
Answer:
0.5
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Answer:
9 1/3
Step-by-step explanation:
1. Make 4 2/3 into a improper fraction
4 2/3= 14/3
2. Keep, change, flip
14/3 x 2/1
3. Multiply
14/3 x 2/1= 28/3
4. Simplify
28/3= 9 1/3
(btw keep, change, flip basically means to keep the first fraction the way it is, change the division sign to a multiplication sign, then flip the second fraction so the original denominator is the new numerator, and vise versa.)
Answer:
Step-by-step explanation:
The Universal Set, n(U)=2092
Let the number who take all three subjects, 
Note that in the Venn Diagram, we have subtracted from each of the intersection of two sets.
The next step is to determine the number of students who study only each of the courses.
![n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x](https://tex.z-dn.net/?f=n%28S%5C%3Aonly%29%3D1232-%5B103-x%2Bx%2B23-x%5D%3D1106%2Bx%5C%5Cn%28F%5C%3A%20only%29%3D879-%5B103-x%2Bx%2B14-x%5D%3D762%2Bx%5C%5Cn%28R%5C%3Aonly%29%3D114-%5B23-x%2Bx%2B14-x%5D%3D77%2Bx)
These values are substituted in the second Venn diagram
Adding up all the values
2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]
2092=2085+x
x=2092-2085
x=7
The number of students who have taken courses in all three subjects,
