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mihalych1998 [28]
3 years ago
5

What is the closest perfect square greater than 54

Mathematics
1 answer:
Anna35 [415]3 years ago
6 0

Answer:

64

Step-by-step explanation:

Perfect squares are integers multiplied by themselves.

  • 2 times 2  = 4
  • 3 times 3  = 9
  • 4 times 4  = 15

The closest perfect squares to 54 are 49 (7^2) and 64 (8^2).

49 is less than 54, so that's ruled out.

Therefore, the closest perfect square to 54 that is greater than it is 64.

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In what rate of interest Rs 4000 amount to Rs 6000 in 2year​
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Principal = Rs 4000

Amount = Rs 6000

Time = 2 years

Rate = ?

Amount = principal + simple interest

Rs 6000 = Rs 4000 + simple interest

simple interest = Rs 6000 - Rs 4000 = Rs 2000

Simple interest = P*R*T/100

Rs 2000 = Rs 4000* R*2/100

R = 100/4 = 25%

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2 years ago
HELP PLS
Maru [420]
Um we need to see the diagram in order to answer this question sorry...but have a good day :)
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Sams brother is 7 years older than Sam. His mother is 4 less than 3 times sams age. Their combined age is 63. How old isn’t Sam,
statuscvo [17]

The answer is 14. This is because 63=3+x+3x-4. Then You just subtract it and then you get 64=4x. Then you just divide it and then you get x=16.

4 0
3 years ago
Find the probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if:a) a
lara31 [8.8K]

Answer:

A) 0.0009765625

B) 0.0060466176

C) 2.7756 x 10^(-17)

Step-by-step explanation:

A) This problem follows a binomial distribution. The number of successes among a fixed number of trials is; n = 10

If a 0 bit and 1 bit are equally likely, then the probability to select in 1 bit is; p = 1/2 = 0.5

Now the definition of binomial probability is given by;

P(K = x) = C(n, k)•p^(k)•(1 - p)^(n - k)

Now, we want the definition of this probability at k = 10.

Thus;

P(x = 10) = C(10,10)•0.5^(10)•(1 - 0.5)^(10 - 10)

P(x = 10) = 0.0009765625

B) here we are given that p = 0.6 while n remains 10 and k = 10

Thus;

P(x = 10) = C(10,10)•0.6^(10)•(1 - 0.6)^(10 - 10)

P(x=10) = 0.0060466176

C) we are given that;

P((x_i) = 1) = 1/(2^(i))

Where i = 1,2,3.....,n

Now, the probability for the different bits is independent, so we can use multiplication rule for independent events which gives;

P(x = 10) = P((x_1) = 1)•P((x_2) = 1)•P((x_3) = 1)••P((x_4) = 1)•P((x_5) = 1)•P((x_6) = 1)•P((x_7) = 1)•P((x_8) = 1)•P((x_9) = 1)•P((x_10) = 1)

This gives;

P(x = 10) = [1/(2^(1))]•[1/(2^(2))]•[1/(2^(3))]•[1/(2^(4))]....•[1/(2^(10))]

This gives;

P(x = 10) = [1/(2^(55))]

P(x = 10) = 2.7756 x 10^(-17)

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3 years ago
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x \ \ \ \ \ \ g(x) \\ -1 \ \ \ \ \ \ 2 \\ -1 \ \ \ \ \ \  -8 \\ 6 \ \ \ \ \ \  -2

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