3 years ago

Solve 6^x+2=10 for x

Mathematics

1 answer:

Basile [38]3 years ago

3 0

X = logs(8) + inn log(6) and n e Z

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sertanlavr [38]

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3 years ago

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TEA [102]

C) 3, 4, 5

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3 years ago

Distance (1,-3) and (7,-8)

GuDViN [60]

Answer:

√61

Step-by-step explanation:

Using

√(y2-y1)^2 + (x2-x1)^2

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3 years ago

Y/2=2/5 solve one step equation?

neonofarm [45]

Step-by-step explanation:

y/2=2/5

5y=4

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3 years ago

In the pulley system shown in this figure, MQ = 30 mm, NP = 10 mm, and QP = 21 mm. Find MN.

ankoles [38]

<h2>Answer:</h2>

$\boxed{\overline{MN}=37.96}$

<h2>Step-by-step explanation:</h2>

For a better understanding of this problem, see the figure below. Our goal is to find $\overline{MN}$ . Since:

$\angle MRS=\angle MQP=90^{\circ} \\ \\ \overline{MQ}=\overline{MR}=30mm$

and $\overline{MN}$ is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:

$\overline{RN}=\overline{QN}$

By Pythagorean theorem, for triangle NQP:

$\overline{QN}=\sqrt{\overline{NP}^2+\overline{QP}^2} \\ \\ \overline{QN}=\sqrt{10^2+21^2} \\ \\ \overline{QN}=\sqrt{541}$

Applying Pythagorean theorem again, but for triangle MQN:

$\overline{MN}=\sqrt{\overline{MQ}^2+\overline{QN}^2} \\ \\ \overline{MN}=\sqrt{30^2+(\sqrt{541})^2} \\ \\ \boxed{\overline{MN}=37.96}$

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3 years ago