Answer:
ME TOOO SO ONCE U FINISH HELPING THEM PLSSSS HELP ME:(((
Step-by-step explanation:
Answer:
ima say 260. .................
Answer:
Part 1) ![x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-2x-2%3D%28x-1-%5Csqrt%7B3%7D%29%28x-1%2B%5Csqrt%7B3%7D%29)
Part 2) ![x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-6x%2B4%3D%28x-3-%5Csqrt%7B5%7D%29%28x-3%2B%5Csqrt%7B5%7D%29)
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
![ax^{2} +bx+c=0](https://tex.z-dn.net/?f=ax%5E%7B2%7D%20%2Bbx%2Bc%3D0)
is equal to
![x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-b%28%2B%2F-%29%5Csqrt%7Bb%5E%7B2%7D-4ac%7D%7D%20%7B2a%7D)
Part 1)
in this problem we have
![x^{2} -2x-2=0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-2x-2%3D0)
so
![a=1\\b=-2\\c=-2](https://tex.z-dn.net/?f=a%3D1%5C%5Cb%3D-2%5C%5Cc%3D-2)
substitute in the formula
![x=\frac{-(-2)(+/-)\sqrt{-2^{2}-4(1)(-2)}} {2(1)}\\\\x=\frac{2(+/-)\sqrt{12}} {2}\\\\x=\frac{2(+/-)2\sqrt{3}} {2}\\\\x_1=\frac{2(+)2\sqrt{3}} {2}=1+\sqrt{3}\\\\x_2=\frac{2(-)2\sqrt{3}} {2}=1-\sqrt{3}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-2%29%28%2B%2F-%29%5Csqrt%7B-2%5E%7B2%7D-4%281%29%28-2%29%7D%7D%20%7B2%281%29%7D%5C%5C%5C%5Cx%3D%5Cfrac%7B2%28%2B%2F-%29%5Csqrt%7B12%7D%7D%20%7B2%7D%5C%5C%5C%5Cx%3D%5Cfrac%7B2%28%2B%2F-%292%5Csqrt%7B3%7D%7D%20%7B2%7D%5C%5C%5C%5Cx_1%3D%5Cfrac%7B2%28%2B%292%5Csqrt%7B3%7D%7D%20%7B2%7D%3D1%2B%5Csqrt%7B3%7D%5C%5C%5C%5Cx_2%3D%5Cfrac%7B2%28-%292%5Csqrt%7B3%7D%7D%20%7B2%7D%3D1-%5Csqrt%7B3%7D)
therefore
![x^{2} -2x-2=(x-(1+\sqrt{3}))(x-(1-\sqrt{3}))](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-2x-2%3D%28x-%281%2B%5Csqrt%7B3%7D%29%29%28x-%281-%5Csqrt%7B3%7D%29%29)
![x^{2} -2x-2=(x-1-\sqrt{3})(x-1+\sqrt{3})](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-2x-2%3D%28x-1-%5Csqrt%7B3%7D%29%28x-1%2B%5Csqrt%7B3%7D%29)
Part 2)
in this problem we have
![x^{2} -6x+4=0](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-6x%2B4%3D0)
so
![a=1\\b=-6\\c=4](https://tex.z-dn.net/?f=a%3D1%5C%5Cb%3D-6%5C%5Cc%3D4)
substitute in the formula
![x=\frac{-(-6)(+/-)\sqrt{-6^{2}-4(1)(4)}} {2(1)}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B-%28-6%29%28%2B%2F-%29%5Csqrt%7B-6%5E%7B2%7D-4%281%29%284%29%7D%7D%20%7B2%281%29%7D)
![x=\frac{6(+/-)\sqrt{20}} {2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B6%28%2B%2F-%29%5Csqrt%7B20%7D%7D%20%7B2%7D)
![x=\frac{6(+/-)2\sqrt{5}} {2}](https://tex.z-dn.net/?f=x%3D%5Cfrac%7B6%28%2B%2F-%292%5Csqrt%7B5%7D%7D%20%7B2%7D)
![x_1=\frac{6(+)2\sqrt{5}}{2}=3+\sqrt{5}](https://tex.z-dn.net/?f=x_1%3D%5Cfrac%7B6%28%2B%292%5Csqrt%7B5%7D%7D%7B2%7D%3D3%2B%5Csqrt%7B5%7D)
![x_2=\frac{6(-)2\sqrt{5}}{2}=3-\sqrt{5}](https://tex.z-dn.net/?f=x_2%3D%5Cfrac%7B6%28-%292%5Csqrt%7B5%7D%7D%7B2%7D%3D3-%5Csqrt%7B5%7D)
therefore
![x^{2} -6x+4=(x-(3+\sqrt{5}))(x-(3-\sqrt{5}))](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-6x%2B4%3D%28x-%283%2B%5Csqrt%7B5%7D%29%29%28x-%283-%5Csqrt%7B5%7D%29%29)
![x^{2} -6x+4=(x-3-\sqrt{5})(x-3+\sqrt{5})](https://tex.z-dn.net/?f=x%5E%7B2%7D%20-6x%2B4%3D%28x-3-%5Csqrt%7B5%7D%29%28x-3%2B%5Csqrt%7B5%7D%29)
Answer:
1.15
Step-by-step explanation:
P/n = 1.15
Price is 1.15 per kiwi
3 19/125
You can take any number, such as 3.152, and write a 1 as the denominator to make it a fraction and keep the same value, like this:
3.152 / 1
To get rid of the decimal point in the numerator, we count the numbers after the decimal in 3.152, and multiply the numerator and denominator by 10 if it is 1 number, 100 if it is 2 numbers, 1000 if it is 3 numbers, and so on.
Therefore, in this case we multiply the numerator and denominator by 1000 to get the following fraction:
3152 / 1000
Then, we need to divide the numerator and denominator by the greatest common divisor (GCD) to simplify the fraction.
The GCD of 3152 and 1000 is 8. When we divide the numerator and denominator by 8, we get the following:
394 / 125
Therefore, 3.152 as a fraction is as follows:
394 / 125